why string is not showing ?

[vknehra10]

if(choice==1)
	  {		  
             System.out.println("Enter Client Name : ");
             Scanner cn=new Scanner(System.in);
             String client=cn.nextLine();
	  }
             else
                System.out.println("Wrong Choice ");				 
  
       if(choice==2)
	  {		  
             System.out.println(client);
	  }
  
         else
                System.out.println("Wrong Choice ");

why it is not print "client"

"Error : cannot find symbol"

[SurfMan]

Variable client is defined in the block of if(choice ==1){...}. In other words, that's the scope. A variable can't be seen outside the scope. So you should define it one block higher, somewhere above the first if.

String client = null;
if(choice==1) {       
    System.out.println("Enter Client Name : ");
    Scanner cn=new Scanner(System.in);
    client=cn.nextLine();
}
else {
    System.out.println("Wrong Choice ");                 
}

[vknehra10]

Variable client is defined in the block of if(choice ==1){...}. In other words, that's the scope. A variable can't be seen outside the scope. So you should define it one block higher, somewhere above the first if.

String client = null;
if(choice==1) {       
    System.out.println("Enter Client Name : ");
    Scanner cn=new Scanner(System.in);
    client=cn.nextLine();
}
else {
    System.out.println("Wrong Choice ");                 
}

but when i use string befor if statement ...

result showing is wrong choice even i choice correct and enter client name it cannot print client name....

[vknehra10]

it print "wrong choice" too why...

[Norm]

it print "wrong choice" too why...

What is the value in choice when it prints that message? Add it to the println statement to see.

[gozzy]

You need to read up on the difference between stringing if statements and the use of if..else. That's the reason why 'wrong choice' is shown even when the choice is 1

[jim829]

And don't do this:

else 
  System.out.println("Wrong Choice ");

Do this - always!

else {
      System.out.println("Wrong Choice "); 
 }

For any construct that requires {}, always use them, even for single lines.

Regards,
Jim

[vknehra10]

What is the value in choice when it prints that message? Add it to the println statement to see.

i have two option in choices

1 >>Enter User
2 >>Check list

when user choose 1
my if code run and it asked "Enter client name"

den i want after enter the name name will show ....

but wrong choice also prints along with the name...

[gozzy]

I've already given you a big hint as to why that happens. You need to study the use of if..else