Can someone explain ReGex ?

[asdfg]

package DO;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class SubStr
{
	 public static void main( String args[] ) throws FileNotFoundException{
	 
		 File file = new File ("kontrolinis");
		 Scanner sken = new Scanner (file);
	
		 
	
	 String line = sken.nextLine ();
	
	 
	 String pattern = "(.*)(\\d)(.*)";
	
	
	 Pattern r = Pattern.compile(pattern);
	
	 
	
	 Matcher m = r.matcher(line);
	
			 if (m.find( )) {
			 System.out.println( m.group(0) );
			 System.out.println( m.group(1) );
			 System.out.println( m.group(2) );
		 }
		 
					 else {
				 System.out.println("NO MATCH");
				 }
		
	 }

}

Text file:
Toyota; auris - 4.0; 5
Audi ; 100 - 1.8; 3
BMW ...
...

The questions comes about this code.
I dont understand 20th line 'String pattern' value. Why so many () ?

23th line is also confusing, what pattern.compile do?

Matcher somehow create these groups too?

[Norm]

Pattern matching and regular expressions are more advanced topics.

What are you trying to do that needs them?

There is some discussion about regular expressions in the Pattern class. See the API doc for the Pattern class: Pattern (Java Platform SE 8 )
Also see the tutorial: http://docs.oracle.com/javase/tutori...gex/index.html

[asdfg]

For example text file contains:
The bird flies around.
The beer walks around.

Combing loop and regex, there should be possible to get console output :
The bird flies
The beer walks

So I wish to know how to make.
Perhaps even possible to skip Integer values and so on.

[Norm]

What have you tried?

Look at the samples on the Pattern class's API doc and the String class's split method?

This seems like an advanced assignment for a beginning student.

I suggest you work with the String class's methods to find and extract parts of a String to create other Strings.

[asdfg]

package DO;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
 
public class Splits {
   
    public static void main(String[] args) throws FileNotFoundException {
   
   Scanner sn = new Scanner ( new File ("just")    );
    
    
    while ( sn.hasNext () )
    {
       String om = sn.nextLine ();
       String[] sentenceArray = om.split(":");
    
       System.out.println ( sentenceArray[1]  );  
    }
    
 sn.close ();       
             
             
    }
}

With split is fine
However i wish to know how to split this line.
Text:
On the road is: car, in the car is - 3 humans.

How to split it twice and have output result:
in the car

[Norm]

how to split this line.

I'd use the String class's methods to locate the desired sub string and extract it.

What is in the sentenceArray array after the split? See the Arrays class's toString method for printing an array's contents.

[asdfg]

What is in the sentenceArray array after the split? See the Arrays class's toString method for printing an array's contents.

sentenceArray [0] text before " : "
[1] text after " : "

[Norm]

how to split this line.
On the road is: car, in the car is - 3 humans.

You need a way to find the two boundaries for the desired text you want to extract. What comes before it and what comes after it?
I think the String class's methods would work better than a regular expression.

[asdfg]

substring (21,29) can do this.
But i dont know how to perform that with split() method?

[Norm]

how to perform that with split() method?

I'm not sure a regular expression with the split method is the best way to solve that problem.