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  1. #1
    AAChaoshand's Avatar
    AAChaoshand is offline Member
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    Default String Array assistance

    I just finished up number and string arrays and once again I like to generate my own code to help me along. I got everything working except the loop and getting the other three elements to be accepted. I swear, getting my brain to switch gears from telecom engineer to programmer is hard, at least for me....

    So the goal here is to present a user with 6 options to type. Only 4 of those are indexes in an array but they don't know that. If they pick the wrong word, they are supposed to guess again until they get it right. While the conditions give the correct responses, we terminate the loop if the wrong response does not loop it again. I have a feeling I am close but just don't get it....
    Java Code:
    import java.util.Scanner;
    
    
    public class Application2 {
    	
    	public static void main(String[] args){
    		
    		Scanner input = new Scanner(System.in);
    		
    		//String Array called words with 4 values
    		String[] words = new String[4];
    		
    		//Now we have defined each element at each index 0-3 (4 indexes total)
    		words[0] = "Apple";
    		words[1] = "Ball";
    		words[2] = "Tree";
    		words[3] = "Car";
    		
    		//This is easy enough to tell what it does, it prints stuff out
    		System.out.println("Pick a word:");
    		System.out.println("1. Apple ");
    		System.out.println("2. Ball ");
    		System.out.println("3. Tree ");
    		System.out.println("4. Car ");
    		System.out.println("5. Computer " );
    		System.out.println("6. Bricks");
    		
    		String word = input.nextLine();
    		
    		/*Here we are going to create a loop that will enable us to pick the right word.
    		 * This is achieved by looping until we get the desired word.
    		 */
    		int i;
    		
    		for(i = 0; i<words.length; i++){
    			if(i != 0){
    			if(word.equalsIgnoreCase(words[i])){
    				System.out.println("You picked the right word!");
    				i = 0;
    				break;
    				}
    			}
    		
    			else if(word != words[i]){
    				System.out.println("Please try again!");	
    				i = 3;
    			}
    			
    		}
    		
    	}
    	
    }
    Last edited by AAChaoshand; 01-15-2015 at 04:35 AM.

  2. #2
    AAChaoshand's Avatar
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    Default Re: String Array assistance

    Cleaned up the code a bit after looking at it for a bit.


    Java Code:
    import java.util.Scanner;
    
    
    public class Application2 {
    	
    	public static void main(String[] args){
    		
    		Scanner input = new Scanner(System.in);
    		
    		//String Array called words with 4 values
    		String[] words = new String[4];
    		
    		//Now we have defined each element at each index 0-3 (4 indexes total)
    		words[0] = "Apple";
    		words[1] = "Ball";
    		words[2] = "Tree";
    		words[3] = "Car";
    		
    		//This is easy enough to tell what it does, it prints stuff out
    		System.out.println("Pick a word:");
    		System.out.println("1. Apple ");
    		System.out.println("2. Ball ");
    		System.out.println("3. Tree ");
    		System.out.println("4. Car ");
    		System.out.println("5. Computer " );
    		System.out.println("6. Bricks");
    		
    		String word = input.nextLine();
    		
    		/*Here we are going to create a loop that will enable us to pick the right word.
    		 * This is achieved by looping until we get the desired word.
    		 */
    		int i;
    		
    		for(i = 0; i<words.length; i++){
    			if(word.equalsIgnoreCase(words[i])){
    				System.out.println("You picked the right word!");
    				break;
    				}
    			
    			else if(word != words[i]){
    				System.out.println("Please try again!");	
    			}
    			
    		}
    		
    	}
    	
    }

  3. #3
    jim829 is offline Senior Member
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    Default Re: String Array assistance

    For String variables a and b, use a.equals(b) or !a.equals(b). Don't use == or !=.

    Regards,
    Jim
    The JavaTM Tutorials | SSCCE | Java Naming Conventions
    Poor planning on your part does not constitute an emergency on my part

  4. #4
    AAChaoshand's Avatar
    AAChaoshand is offline Member
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    Default Re: String Array assistance

    Hi Jim,

    Thanks for the tip. I was wondering what the "not equals" was for Strings. I'm kinda researching extra stuff while doing the at my own pace course on udemy so that helps me a lot. Now the problem is, why is it not looping if it is wrong and I am still getting some odd output.

    Revised Code:

    Java Code:
    import java.util.Scanner;
    
    
    public class Application2 {
    	
    	public static void main(String[] args){
    		
    		Scanner input = new Scanner(System.in);
    		
    		//String Array called words with 4 values
    		String[] words = new String[4];
    		
    		//Now we have defined each element at each index 0-3 (4 indexes total)
    		words[0] = "Apple";
    		words[1] = "Ball";
    		words[2] = "Tree";
    		words[3] = "Car";
    		
    		//This is easy enough to tell what it does, it prints stuff out
    		System.out.println("Pick a word:");
    		System.out.println("1. Apple ");
    		System.out.println("2. Ball ");
    		System.out.println("3. Tree ");
    		System.out.println("4. Car ");
    		System.out.println("5. Computer " );
    		System.out.println("6. Bricks");
    		
    		String word = input.nextLine();
    		
    		/*Here we are going to create a loop that will enable us to pick the right word.
    		 * This is achieved by looping until we get the desired word.
    		 */
    		int i;
    		
    		for(i = 0; i<words.length; i++){
    			if(word.equalsIgnoreCase(words[i])){
    				System.out.println("You picked the right word!");
    				break;
    				}
    		
    			else if(!word.equals(words[i])){
    				System.out.println("Please try again!");	
    
    			}
    			
    		}
    		
    	}
    	
    }
    Console Output:

    Pick a word:
    1. Apple
    2. Ball
    3. Tree
    4. Car
    5. Computer
    6. Bricks
    apple
    You picked the right word!

    Pick a word:
    1. Apple
    2. Ball
    3. Tree
    4. Car
    5. Computer
    6. Bricks
    ball
    Please try again!
    You picked the right word!

    Now I know why apple works, the loop still has i = 0. My question is how to I get it to increment to check the other indexes before saying I am wrong then right? Sorry if I am full of questions but I am trying to learn this stuff. Trying to pick Java up as a hobby and maybe more later on in the years.

  5. #5
    jim829 is offline Senior Member
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    Default Re: String Array assistance

    Just use the loop to check for the correct word. Initialize a boolean to false. If they get it, set the boolean to true and break out of the loop. If they don't get it,the loop will end naturally with the boolean set to false. Then check the state of the boolean to print the success or failure message. There may be a better way to do it (like using a hash map instead of an array) but this was the first that came to me.

    Regards,
    Jim
    The JavaTM Tutorials | SSCCE | Java Naming Conventions
    Poor planning on your part does not constitute an emergency on my part

  6. #6
    AAChaoshand's Avatar
    AAChaoshand is offline Member
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    Default Re: String Array assistance

    Ok, I took your advice but I'm still scatter brained (Probably because once I get home from work I start learning more Java and don't stop till I go to bed and end up seeing code in my sleep). Your method does make the code look much cleaner. I am still having issues getting it to loop. I'm still working on it but here is what I have so far. No answers please, just point me in the right direction

    the FOR loop is the only way I know as of right now to get all the indexes to pop and get checked. If there is another way I am open to hear it but please understand I'm still learning just the basics.

    Java Code:
    import java.util.Scanner;
    
    
    public class Application2 {
    	
    	public static void main(String[] args){
    		
    		Scanner input = new Scanner(System.in);
    		
    		//String Array called words with 4 values
    		String[] words = new String[4];
    		
    		//Now we have defined each element at each index 0-3 (4 indexes total)
    		words[0] = "Apple";
    		words[1] = "Ball";
    		words[2] = "Tree";
    		words[3] = "Car";
    		
    		//This is easy enough to tell what it does, it prints stuff out
    		System.out.println("Pick a word:");
    		System.out.println("1. Apple ");
    		System.out.println("2. Ball ");
    		System.out.println("3. Tree ");
    		System.out.println("4. Car ");
    		System.out.println("5. Computer " );
    		System.out.println("6. Bricks");
    		
    		String word = input.nextLine();
    		
    		/*Here we are going to create a loop that will enable us to pick the right word.
    		 * This is achieved by looping until we get the desired word.
    		 */
    		
    		int i;
    		
    
    		
    		for(i = 0; i<words.length; i++){
    			boolean check = false;
    			if(word.equalsIgnoreCase(words[i])){
    				System.out.println("You picked the right word!");
    				check = true;
    				if(check = true){
    				break;
    				}
    				else
    					System.out.println("Please try again!");
    			}
    
    		}
    		
    	}
    	
    }
    Last edited by AAChaoshand; 01-15-2015 at 05:31 AM.

  7. #7
    jim829 is offline Senior Member
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    Default Re: String Array assistance

    Move the boolean initialization outside the for loop. And get rid of the else print statement. Then, outside the loop,
    simply check the state of the boolean. And don't use = use ==. = is an assignment. == is for checking primitive equality. And equals() as I said earlier is for checking object equality.

    Regards,
    Jim
    The JavaTM Tutorials | SSCCE | Java Naming Conventions
    Poor planning on your part does not constitute an emergency on my part

  8. #8
    pbrockway2 is offline Moderator
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    Default Re: String Array assistance

    If they pick the wrong word, they are supposed to guess again until they get it right.
    If they are supposed to guess again shouldn't the input.nextLine() statement go inside a loop somewhere? That way their next guess will actually be read.

    I'm pretty sure there are *two* loops involved here. So give it some thought before you rush into code. An outer loop could use a boolean as Jim suggests to keep going until they guess correctly. And the inner for loop could check their answer against each of the words in the array. The inner loop is more like you had before, but note you don't need a special "is not equal to" for the strings:

    Java Code:
    for(i = 0; i<words.length; i++){
        if(word.equalsIgnoreCase(words[i])){
            // code if they got it right
        } else {
            //code for not equal goes here
        }
    }
    If you ever do need to say "is not equal to" you would use the condition !foo.equals(bar) or !foo.equalsIgnoreCase(bar).

  9. #9
    AAChaoshand's Avatar
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    Default Re: String Array assistance

    Working on both solutions now. I have a hard time visualizing everything is my problem and then coming up with a code for the end goal.

  10. #10
    jim829 is offline Senior Member
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    Default Re: String Array assistance

    Quote Originally Posted by pbrockway2 View Post
    I'm pretty sure there are *two* loops involved here.
    [code]
    Yeah. I was focusing on the inner loop to check the answer. There must also be a way to reprompt for user input.

    Regards,
    Jim
    The JavaTM Tutorials | SSCCE | Java Naming Conventions
    Poor planning on your part does not constitute an emergency on my part

  11. #11
    AAChaoshand's Avatar
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    Default Re: String Array assistance

    My next question is how can I increment the outer loop while checking the inner loop? I have to input something in order for "i" to increment at this point and the correct answer will be based upon attempts. I may just take a break for the night and pick this up tomorrow, I'm just getting frustrated and losing site at the big picture.

    Java Code:
    import java.util.Scanner;
     
     
    public class Application3 {
         
        public static void main(String[] args){
             
            Scanner input = new Scanner(System.in);
             
            //String Array called words with 4 values
            String[] words = new String[4];
             
            //Now we have defined each element at each index 0-3 (4 indexes total)
            words[0] = "Apple";
            words[1] = "Ball";
            words[2] = "Tree";
            words[3] = "Car";
             
            //This is easy enough to tell what it does, it prints stuff out
            System.out.println("Pick a word:");
            System.out.println("1. Apple ");
            System.out.println("2. Ball ");
            System.out.println("3. Tree ");
            System.out.println("4. Car ");
            System.out.println("5. Computer " );
            System.out.println("6. Bricks");
             
            /*Here we are going to create a loop that will enable us to pick the right word.
             * This is achieved by looping until we get the desired word.
             */
            int i;
            
            for(i = 0; i<words.length; i++){ 
                String word = input.nextLine();
                //Correct Answer Coding which checks word against the array
                if(word.equalsIgnoreCase(words[i])){
                    System.out.println("You picked the right word!");
                    break;   
                    
                } else {
                //Incorrect answer prompting them to try again
                	System.out.println("Please try again!");
                }
                 
            }
             
        }
         
    }

  12. #12
    jim829 is offline Senior Member
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    Default Re: String Array assistance

    I think you posted old code. Anyway, here is pseudo code to describe the checking loop:

    Java Code:
    boolean check = false;
    for i loop
          if correct word
              check = true;
              exit loop
    end loop
    
    if (check)  
         correct guess.
      else
         incorrect guess
    end if
    Regards,
    Jim
    Last edited by jim829; 01-15-2015 at 06:22 AM.
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  13. #13
    pbrockway2 is offline Moderator
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    Default Re: String Array assistance

    ....
    Last edited by pbrockway2; 01-15-2015 at 06:24 AM. Reason: Second thoughts

  14. #14
    AAChaoshand's Avatar
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    Default Re: String Array assistance

    Yeah, I'm just stupid I know, I just don't got the experience y'all have, not even close... I'm a fresh from "scratch never seen code beginner" that has went through about 4 hours of a Java course and is trying his best with what he remembers from a semester 3 years ago. Here is what I have left over from the boolean version. Have a nice night or day depending on where you live.

    Java Code:
    import java.util.Scanner;
    
    
    public class Application2 {
    	
    	public static void main(String[] args){
    		
    		Scanner input = new Scanner(System.in);
    		
    		//String Array called words with 4 values
    		String[] words = new String[4];
    		
    		//Now we have defined each element at each index 0-3 (4 indexes total)
    		words[0] = "Apple";
    		words[1] = "Ball";
    		words[2] = "Tree";
    		words[3] = "Car";
    		
    		//This is easy enough to tell what it does, it prints stuff out
    		System.out.println("Pick a word:");
    		System.out.println("1. Apple ");
    		System.out.println("2. Ball ");
    		System.out.println("3. Tree ");
    		System.out.println("4. Car ");
    		System.out.println("5. Computer " );
    		System.out.println("6. Bricks");
    		
    		String word = input.nextLine();
    		
    		/*Here we are going to create a loop that will enable us to pick the right word.
    		 * This is achieved by looping until we get the desired word.
    		 */
    		
    		int i;
    		boolean check = false;
    		
    		for(i = 0; i<words.length; i++){
    			if(word.equalsIgnoreCase(words[i])){
    				check = true;
    				break;
    				}
    			}
    		
    		if(check == true){
    			System.out.println("You picked the right word!");
    		}
    		else{
    			System.out.println("Please try again");
    		}
    		
    	}
    	
    }

  15. #15
    pbrockway2 is offline Moderator
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    Default Re: String Array assistance

    A couple of little changes - they don't do anything, but they make it easier to move foward:

    (a) Move the "int i;" into the for statement. "for(int i = 0; etc". It is considered good practice for variable declarations to be as close as possible to where they are used. This way i will only be "visible" inside the for loop and you won't accidently get a strange value if you use i later on. Not that you're likely to ... but it's a good habit to practice from the start.

    (b) Move the "boolean check=false;" line to before the "input.nextLine();" line. The reason for that is that you want the input part to be inside a loop (not the for loop!) so the user can keep entering guesses, but you want the check declaration and initialisation to happen once only before that loop starts.

    With those little changes done you are in a position to add a loop to get the guessing process to repeat over and over while check is false. Ask yourself what sort of loop should it be. And ask yourself which lines of of your existing code should it wrap - that is, which lines of your code do you want to repeat over and over again.

    [Edit] And the two closing } at the end of the for loop are indented too much. This doesn't affect the code at all, but formatting is a skill that is only aquired through habit so start now. Also you'd be surprised how much the appearance of code to the eye affects the appreciation of its logic by the mind. We are visual animals.
    Last edited by pbrockway2; 01-15-2015 at 07:36 AM. Reason: tired

  16. #16
    gimbal2 is offline Just a guy
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    Default Re: String Array assistance

    I see people complain about indentation more often; keep in mind that often in the editor of the guy posting the code it may just look fine. Its most likely a problem of mixing tabs and spaces.

    If we're on the topic of making minor adjustments, consider a little readability change. Rather than:

    Java Code:
    boolean check = false;
    
    if(check == true){
     // ...
    }
    try this on for size:

    Java Code:
    boolean wordMatches = false;
    
    if(wordMatches){
      // ...
    }
    The code just speaks more to you, doesn't it?

    Also consider this: when the comments people make are really petty spelling type of things, you're on the right track ;)
    Last edited by gimbal2; 01-15-2015 at 10:50 AM.
    "Syntactic sugar causes cancer of the semicolon." -- Alan Perlis

  17. #17
    AAChaoshand's Avatar
    AAChaoshand is offline Member
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    Default Re: String Array assistance

    My solution to the code after sitting down with a fresh head is below. I cleaned up the curly brackets the best I could, I don't remember ever doing it that way. I remember our professor back in my college days always had us do it like this:

    Java Code:
    {
    public class Application2
    
         public static void main)String[] args)
         {
    //Code here
         }
    
    }
    The above made sense to me and made it easy for me to see what ended where but this other method also makes sense. I'm still not 100% sure on how I got the code to work but at least I got a better understanding now than I did last night. I appreciate all of the help. If a project that I created out of the blue gave me this much trouble I can only imagine how hard the rest of the course will be....

    Anyways, without further delay, below is the corrected code as far as I can tell, everything works as intended.
    Java Code:
    import java.util.Scanner;
    
    
    public class Application2 {
    	
    	public static void main(String[] args) {
    		
    		Scanner input = new Scanner(System.in);
    		
    		//String Array called words with 4 values
    		String[] words = new String[4];
    		
    		//Now we have defined each element at each index 0-3 (4 indexes total)
    		words[0] = "Apple";
    		words[1] = "Ball";
    		words[2] = "Tree";
    		words[3] = "Car";
    		
    		//This is easy enough to tell what it does, it prints stuff out
    		System.out.println("Pick a word:");
    		System.out.println("1. Apple ");
    		System.out.println("2. Ball ");
    		System.out.println("3. Tree ");
    		System.out.println("4. Car ");
    		System.out.println("5. Computer " );
    		System.out.println("6. Bricks");
    		
    		/*Here we are going to create a loop that will enable us to pick the right word.
    		 * This is achieved by looping until we get the desired word.
    		 */
    		
    		boolean check = false;
    		while(check == false) {
    			String word = input.nextLine();
    			
    			for( int i = 0; i<words.length; i++) {
    				if(word.equalsIgnoreCase(words[i])) {
    					check = true;
    					break;
    				}
    				else {
    					System.out.println("Please try again");
    				}
    			}
    		}
    		
    		if(check == true) {
    			System.out.println("You picked the right word!");
    		}
    		
    	}
    	
    }

    And.....disregard something is still hosed....
    Last edited by AAChaoshand; 01-16-2015 at 04:29 AM.

  18. #18
    AAChaoshand's Avatar
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    Default Re: String Array assistance

    Ok, latest revised code. I sat there and thought about it hard. I didn't want the loop to include "Please try again" over and over while it cycled the indexes in the for loop. Instead, I put the if condition after the for loop but inside the while loop so the value was still checked and printed if needed.

    Java Code:
    import java.util.Scanner;
     
     
    public class Application2 {
         
        public static void main(String[] args) {
             
            Scanner input = new Scanner(System.in);
             
            //String Array called words with 4 values
            String[] words = new String[4];
             
            //Now we have defined each element at each index 0-3 (4 indexes total)
            words[0] = "Apple";
            words[1] = "Ball";
            words[2] = "Tree";
            words[3] = "Car";
             
            //This is easy enough to tell what it does, it prints stuff out
            System.out.println("Pick a word:");
            System.out.println("1. Apple ");
            System.out.println("2. Ball ");
            System.out.println("3. Tree ");
            System.out.println("4. Car ");
            System.out.println("5. Computer " );
            System.out.println("6. Bricks");
             
            /*Here we are going to create a loop that will enable us to pick the right word.
             * This is achieved by looping until we get the desired word.
             */
             
            boolean check = false;
            while(check == false) {
                String word = input.nextLine();
                 
                for(int i = 0; i<words.length; i++) {
                    if(word.equalsIgnoreCase(words[i])) {
                        check = true;
                        break;
                    }
                }
                
                 if(check == false){
                	System.out.println("Please try again!");
                }
            }
             
            if(check == true) {
                System.out.println("You picked the right word!");
            } 
        }
    }

    Here is my biggest question. I did have the aha moment but now I'm confused. The for statement should keep looping itself as long as the check is not equal to true. When that loop cycles and does an i++, why does the next if statement get checked when the original for loop never broke out? Is it because the while loop hasn't broken and re-initiates the entire loop or am I not understanding this correctly?
    Last edited by AAChaoshand; 01-16-2015 at 05:04 AM.

  19. #19
    pbrockway2 is offline Moderator
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    Default Re: String Array assistance

    The for statement should keep looping itself as long as the check is not equal to true. When that loop cycles and does an i++, why does the next if statement get checked when the original for loop never broke out?
    No the for loop will loop until word.equalsIgnoreCase(words[i]) in which case it sets check to true and breaks (stops) or because it has looped words.length times and run out of things to compare. The next if statement gets executed after the for loop. This means that the next for if statement gets executed if the for loop was "broken" but also if the for loop checked every string, found no match and ended "normally".

    In either case the for loops ends and the if second if statement checks ... whether check is false, and, if it is, (because no match is found) it prints the "guess again" message.

    ---

    Does the code function correctly now? It looks like it does, but I haven't check it closely.

    If there is a problem with the code, explain what the code is doing wrong when you run it.

    But even if the code does function as you want it is important to understand what it is doing. If my explanation doesn't make sense, say so.

  20. #20
    AAChaoshand's Avatar
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    Default Re: String Array assistance

    That actually makes sense and is how I thought of it when I initially came up with the correct code. I started looking to deep into it which is a problem for us IT engineers as we always check, check again, and sometimes go to deep. It all makes sense but I am making this a personal case study for myself. I've started a study group on udemy so that others like me can collaborate and work things out so we understand as well. Programming and telecom network engineering are polar opposites when it comes to thought process, at least for me anyways.

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