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  1. #1
    Matrice is offline Member
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    Jul 2014
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    Default Scanner Grade confusion

    Hey all, it's been 6 days since I've started learning Java.
    I have decided to write a code all on my own today. Now, I have something that looks like it should do what I want it do to, but it doesn't. I want it to scan and correctly give the correct output depending on the user's input of a grade score (without the % sign). It seems that whatever I've done, has allowed it to give the 90% A grade no matter what score you input. I am still learning, but I think I am improving. Anyone want to teach me or guide me on this quest to learn?
    Attached Thumbnails Attached Thumbnails Scanner Grade confusion-screen-shot-2014-07-29-1.07.49-pm.png  

  2. #2
    superhaNds is offline Senior Member
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    Default Re: Scanner Grade confusion

    Variable A has the value 90, so if 90 < 100 print A.

    You need another variable to store the input number and check the value against the different grades; .nextLong() returns a value, but you do not use it.

  3. #3
    JosAH's Avatar
    JosAH is offline Moderator
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    Voorschoten, the Netherlands
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    Default Re: Scanner Grade confusion

    Every valid number is less than (or equal to) 100, so the first test always succeeds. For those half open intervals you have to start checking 'from the bottom', i.e. first check for an F, next for a D etc.

    kind regards,

    Build a wall around Donald Trump; I'll pay for it.

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