PhoneBook Application

[jmcquaid1987]

This application is supposed to allow a user to enter the names an phone numbers of up to 20 friends, until the user enters "zzz" or 20 names. Then the console is supposed to display the names and have the user enter a name to get the phone number. Here's my code:

import java.util.Scanner;

public class PhoneBook {

public static void main(String[] args) {
String name;
int phoneNumber;
final int nameAmount=20;
NamesNumbers[] names=new NamesNumbers[nameAmount];
int a;
int b;
final int phoneNumberAmount=20;
final String quit="zzz";
Scanner keyboard=new Scanner(System.in);

while(a < nameAmount && b != phoneNumberAmount) {

if(name != quit) {

for(b=0; b < nameAmount; ++b) {
names[b]=new NamesNumbers();

System.out.print("Enter name or zzz to quit: ");
name=keyboard.nextLine();
names[b].setName(name);

for(a=0; a < phoneNumberAmount; ++a) {
System.out.print("Enter phone number: ");
phoneNumber=keyboard.nextInt();
names[b].setPhoneNumber(a, phoneNumber);
}
}
a++;
}
for(b=0; b < nameAmount; ++b) {
System.out.println("\nPhone numbers of " + names[b].getName());
for(a=0; a < phoneNumberAmount; ++a)
System.out.print(names[b].getPhoneNumber(a) + " ");
System.out.println();
}
}

System.out.print("\n\nEnter a name to see their phone number: ");
name=keyboard.nextLine();

for(b=0; b < names.length; ++b)
if(name.equals(names[b].getName()))
for(a=0; a < phoneNumberAmount; ++a)
System.out.print(names[a].getPhoneNumber(a) + " ");

System.out.println();

}
}


I can't seem to get it correct, every time I correct a compiler error, another set of them appear. Any help would be greatly appreciated!

[Norm]

Please edit your post and wrap your code with code tags:
[code]
YOUR CODE HERE
[/code]
to get highlighting and preserve formatting.

If you get compiler errors, copy the full text and paste it here.

[jmcquaid1987]

import java.util.Scanner;

public class PhoneBook	{

	public static void main(String[] args)	{
		String name;
		int phoneNumber;
		final int nameAmount=20;
		NamesNumbers[] names=new NamesNumbers[nameAmount];
		int a;
		int b;
		final int phoneNumberAmount=20;
		final String quit="zzz";
		Scanner keyboard=new Scanner(System.in);
		
		while(a < nameAmount && b != phoneNumberAmount)	{
		
			if(name != quit)	{
		
			for(b=0; b < nameAmount; ++b)	{
				names[b]=new NamesNumbers();
			
			System.out.print("Enter name or zzz to quit: ");
			name=keyboard.nextLine();
			names[b].setName(name);
		
				for(a=0; a < phoneNumberAmount; ++a)	{
					System.out.print("Enter phone number: ");
					phoneNumber=keyboard.nextInt();
					names[b].setPhoneNumber(a, phoneNumber);
				}
			}
			a++;
			}
			for(b=0; b < nameAmount; ++b)	{
			System.out.println("\nPhone numbers of " + names[b].getName());
			for(a=0; a < phoneNumberAmount; ++a)
				System.out.print(names[b].getPhoneNumber(a) + " ");
			System.out.println();
			}
		}
		
		System.out.print("\n\nEnter a name to see their phone number: ");
		name=keyboard.nextLine();
		
		for(b=0; b < names.length; ++b)
			if(name.equals(names[b].getName()))
				for(a=0; a < phoneNumberAmount; ++a)
					System.out.print(names[a].getPhoneNumber(a) + " ");
					
		System.out.println();
		
	}
}

C:\Users\Justin\Java\Week08>javac PhoneBook.java
PhoneBook.java:16: error: variable a might not have been initialized
while(a < nameAmount && b != phoneNumberAmount) {
^
PhoneBook.java:16: error: variable b might not have been initialized
while(a < nameAmount && b != phoneNumberAmount) {
^
PhoneBook.java:18: error: variable name might not have been initialized
if(name != quit) {
^
3 errors

My apologies for the improper posting

[Norm]

What about the text of the compiler error messages?

[jmcquaid1987]

I get the feeling that there are more issues with my code that are next to come for the compiler.. :/

[gimbal2]

Take a look at the variables the compiler is complaining about:

int a;

What value should a have? 0? -1? 1000? Java can't know and that last thing Java should do is make assumptions; that's what it is complaining about, you need to set an initial value ('initialize it') yourself so there is no chance that the wrong thing is happening.

int a = 0;

That's all.