How to swap the first and last array value

[ecc.soccer]

This is what I have so far, but I am not sure how to fix it... please help... Thanks

public class SwapFandL {

public static void swap(int [] x){
int temp = x[0];
x[0] = x[x.length-1];
x[x.length-1] = temp;


}
public static void main(String[] args){
int [] x = {1, 3, 5, 7, 2, 9};

System.out.print(swap(x));

}
}

[ecc.soccer]

The output should be : 9 3 5 7 2 1

[Junky]

If you get an error then you should copy and paste the full error message and indicate on which line it occurs.

Your swap method has a void return type, therefore there is nothing for the print statement to display. Also, you cannot print an array that way. You need to iterate over the array and print out each element individually.

[ecc.soccer]

This is how I changed it...
and the output I got was : [I@3dd4ab05

public class SwapFandL {

public static int[] swap(int [] x){
int temp = x[0];
x[0] = x[x.length-1];
x[x.length-1] = temp;
return x;

}
public static void main(String[] args){
int [] x = {1, 3, 5, 7, 2, 9};

System.out.print(swap(x));

}
}

[Junky]

Read my entire post above!

[jim829]

Since you are swapping elements of an array (which is a reference) you do not need to return anything. However, to print out the array you need to do what Junky recommended. Another alternative is to the Arrays class. You should find a method in that class that could be of use.

Regards,
Jim