hi everyone,

i need to take year and month as input and generate a calendar for 12months,

i need to rite a jsp page with servlet

can any 1 helpplz

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- 05-05-2008, 04:54 AMveenacalendar of 12months when year is entered
hi everyone,

i need to take year and month as input and generate a calendar for 12months,

i need to rite a jsp page with servlet

can any 1 helpplz - 05-05-2008, 05:03 AMEranga
Did you Goole it. There should be some mathematical way to find it.

- 05-05-2008, 05:08 AMveena
yes i did and cudnt find anything

- 05-05-2008, 05:23 AMEranga
Ok, here is a way.

Code:`N = d + 2m + [3(m+1)/5] + y + [y/4] - [y/100] + [y/400] + 2`

m - moth id(from 1 to 12 respectively)

y - year

Do the calculations and find the N. Keep in mind that to drop the remainder in each [] and only get the whole number. Don't rounding off numbers. Then divide the N by 7. Remainder give the answer, day of the week.

0 - Saturday

1 - Sunday

2 - Monday

3 - Tuesday and so on.

Try it and see. - 05-05-2008, 05:41 AMEranga
Ah, made a mistake in my explanation. Here is an example for today(5/5/2008)

Code:`N = 5 + 2(5) + [3(6)/5] + 2008 + [2008/4] - [2008/100] + [2008/400] + 2`

N = 5 + 10 + 3 + 2008 + 502 - 20 + 5 + 2

N = 2515

**d**is not the number of days of the month. Days spending up to date which we want to processing.

Did you get it? - 05-05-2008, 06:11 AMveena
im trying to write in servlet and get in jsp

- 05-05-2008, 06:13 AMZosden
The way Eranga explain it is correct. except you have to account for leap years. which you do with an array I forget the exact table.

- 05-05-2008, 06:19 AMEranga
- 05-05-2008, 06:24 AMveena
hey Eranga

when u add up N=2501 - 05-05-2008, 06:33 AMEranga
Is it.

Code:`N = 1 + 2(1) + [3(2)/5] + 2008 + [2008/4] - [2008/100] + [2008/400] + 2`

N = 1 + 2 + 1 + 2008 + 502 - 20 + 5 + 2

N = 5 + 2008 + 502 - 20 + 7

N = 2510 - 20 + 12

N = 2502

- 05-05-2008, 06:42 AMveena
let me try again

- 05-05-2008, 06:59 AMZosden
Linky

Try this on for size. - 05-05-2008, 07:00 AMEranga
Go it. I've miss a very important rule there. Really sorry about. Still I remembering this and let you know, because I do those things few years back when I'm in the university for maths.

You have to use numbers 13 and 14 for the months of January and February, with the previous year. In our discussion,

1/1/2008 should be 1/13/2007.

Lets try it.

Code:`N = 1 + 2(13) + [3(14)/5] + 2007 + [2007/4] - [2007/100] + [2007/400] + 2`

N = 1 + 26 + 8 + 2007 + 501 - 20 + 5 + 2

N = 2530

Lets do another example, for 20/2/2008. So the date should be 20/14/2007

Code:`N = 20 + 2(14) + [3(15)/5] + 2007 + [2007/4] - [2007/100] + [2007/400] + 2`

N = 20 + 28 + 9 + 2007 + 501 - 20 + 5 + 2

N = 2552

Keep in mind that, rule only valid for January and February. - 05-05-2008, 07:15 AMveena
yep i got it and did in servlet

when i was searching i got the same formula

any ways thnks very much

its a nice formula though - 05-05-2008, 07:15 AMZosden
I think you can just use the Gregorian calendar I think also.

- 05-05-2008, 08:48 AMEranga
No matter what calender you used, my formula is working. We have used in few projects that formula, when I'm in the University.

- 05-06-2008, 05:03 AMEranga
Hey veena, no need to edit your post time to time. If you expecting the answer in different approaches please let it to others. Because later someone read your thread, really confused. :)