File reading with Scanner

[mik]

Hi guys, thanks for taking the time to help me out!
For those curious about the purpose of the code: I was assigned to create a program that converts a 32-bit binary string into an ipv4 address using java by separating the strings into 8-bit segments and converting them into decimal.

/**
 * @(#)ip.java
 *
 *
 * @author 
 * @version 1.00 2012/8/29
 */
 import java.util.Scanner;
 import java.io.*;
 import java.util.BitSet;
public class ip {
	public static int convert(BitSet barf)
	{
		int rvalue = 0;
		int numset[]={128, 64, 32, 16, 8, 4, 2, 1};
		for(int o=8; o<8; ++o)
		{
			if(barf.get(o))
				rvalue+=numset[o];
			
		}
		return rvalue;
		
	}
        
    /**
     * Creates a new instance of <code>ip</code>.
     */
    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) throws IOException {
        // TODO code application logic here
        
        Scanner bleh = new Scanner(System.in);
        File filename = new File(bleh.nextLine());
        Scanner read =new Scanner(filename);
        int numaddr=read.nextInt();
        BitSet addr[] = new BitSet[numaddr];
        int epsy=0;
        
        for(int i=0; i<numaddr;++i)
        {
        	epsy=read.nextInt();
        	for(int z=0; i<32;++z)
        	{
        		if(epsy%10==1)
        		addr[i].set(z);
        		epsy/=10;
        	}
        }
        for(BitSet crum:addr)
        {
        	System.out.println(convert(crum.get(0, 8))+"."+convert(crum.get(8, 16))+"."+convert(crum.get(16, 24))+"."+convert(crum.get(24, 32)));
        }
      bleh.close();  
      read.close(); 
    }
}

throws the following error when run.

Exception in thread "main" java.util.InputMismatchException: For input string: "11111111111111111111111111111111"
at java.util.Scanner.nextLong(Unknown Source)
at java.util.Scanner.nextLong(Unknown Source)
at ip.main(ip.java:44)

the file I'm feeding it contains the following

4
11111111111111111111111111111111
00000011100000001111111111111111
11110000101010100101010100000111
10101010101010101010101010101010

Thanks for your time, have a great day!

[Junky]

That value is greater than Long.MAX_VALUE.

[Tolls]

Junky's correct, though it would help if you showed the code that threw the exception as well.
The code shown is using getInt, the code that threw that exception used getLong.

Anyway, since you just want the "bits", read in the string and parse each character.