# Thread: Using recursion to print alternating squares?

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Dec 2011
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## Using recursion to print alternating squares?

Hi, I'm trying to use recursion (no loops) to print out descending odd, then ascending even squares less than a certain number.
For examples, squares(5) would print out: 25, 9, 1, 4, 16.
I'm not sure how I would alternate between even/odd, and would really appreciate some help with that.

Right now, I have it so that all squares are printed in descending order. All input is greatly appreciated!

public static void squares(int n)
{
if (n < 1)
{
throw new IllegalArgumentException();
} else
{
System.out.print(n*n);
squares(n-1);
}
}

2. ## Re: Using recursion to print alternating squares?

It's probably easiest just to make one method for the odd squares and one for the even squares. You can also make 2 arrays, one for even, one for odd and at each step just fill the proper array and then make your recursive call.

3. ## Re: Using recursion to print alternating squares?

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