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 01232012, 07:23 PM #1Member
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Sparse Matrix  need help. Array index of out bounds: 1
hi there. first time here. im getting an array index out of bounds on my code. keep checking and simulating it but there no error on my simulating. when i run it, it gives an error arrays out of bounds: 1
any help??
this is my code.
Java Code:import java.util.Scanner; public class Sparse { int num = 0; public void Count_Nonzero(int Arr1[][],int m, int n) { int Row = 0; while(Row<m) { int Col= 0; while(Col<n) { if (Arr1[Row][Col] != 0) { num++; } Col++; } Row++; } } public static void main(String[] args) { Sparse Keyboard = new Sparse(); Scanner scan= new Scanner(System.in); System.out.println("Input rows"); int m=scan.nextInt(); System.out.println("Input Column"); int n=scan.nextInt(); int arr1[][] = new int [m][n]; for(int i=0; i<m;i++){ for(int j=0;j<n;j++){ System.out.println("Enter Element ["+i+"]["+j+"]"); arr1[i][j]=scan.nextInt(); } } Keyboard.sparse(arr1,m,n); } public void sparse(int Arr1[][],int m, int n) { int ArrNew[][] = new int [num+1][3]; ArrNew[0][0]= m; ArrNew[0][1]= n; ArrNew[0][2]= num; int Row = 0; int I=1; while (Row<m) { int Col=0; while(Col<n) { if(Arr1[Row][Col] != 0) { ArrNew[I][0] = Row; ArrNew[I][1] =Col; ArrNew[I][2] = Arr1[Row][Col]; I++; } Col++; } Row++; } for(int i=0; i<m;i++){ for(int j=0;j<n;j++){ System.out.print(""+ArrNew[i][j]+" "); } System.out.println(); } } }
Last edited by JosAH; 01232012 at 08:11 PM. Reason: added [code] ... [/code] tags
 01232012, 07:27 PM #2Moderator
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Re: Sparse Matrix  need help. Array index of out bounds: 1
Please use code tags when posting code.
What is the full exception you are getting, and from what line of code?
 01232012, 07:37 PM #3Member
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Re: Sparse Matrix  need help. Array index of out bounds: 1
sorry. how can you use code tags? newbie here.
the line : Keyboard.sparse(arr1,m,n);
and line : ArrNew[I][0] = Row;
are the problems. getting exception.
 01232012, 08:12 PM #4
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Re: Sparse Matrix  need help. Array index of out bounds: 1
I fixed the tags for you. b.t.w. those Exceptions also mention the line number where the Exception was thrown.
kind regards,
JosBuild a wall around Donald Trump; I'll pay for it.
 01232012, 09:00 PM #5Member
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Re: Sparse Matrix  need help. Array index of out bounds: 1
Make follwing change to remove runtime Error
int ArrNew[][] = new int [m*n][3];
instead
//int ArrNew[][] = new int [num+1][3];
Also make some change to output code block
for(int i=0; i<m;i++){
for(int j=0;j<n;j++){
System.out.print(""+ArrNew[i][j]+" ");
}
System.out.println();
}
coz ArrNew[][] now have more colum
and more rows.......
 01232012, 09:30 PM #6
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