can someone help

[kenson02]

Here is the question that i was ask: write a method isPalindrome() that returns true if the specified number reads the same forward and backward?

here is the code that i wrote?

public static boolean isPalindrome(String s) {
if (s.length() == 0 || s.length() == 1)
return true;
if (s.charAt(0) == s.charAt(s.length() - 1))
return isPalindrome(s.substring(1, s.length() - 1));
return false;
Is it correct?
because on the Test class i find an error that says: cannot invoke isPalindrome() on primitive type int.

[Fubarable]

You'll want to show us the line that causes the error. It looks like you're trying to call this method on an int when it is written to be called on a String. Thus the offending code is not the code you're showing us.

[kenson02]

Actually i will show the whole program.. first i wrote the MyInteger class myself and the TestMyInteger class was provide to me. My problem is what i told u on the first question.

was provided

public class TestMyInteger {
public static void main(String[] args) {
MyInteger n1 = new MyInteger(5);
System.out.println("n1 is even? " + n1.isEven());
System.out.println("n1 is prime? " + n1.isPrime());
System.out.println("15 is prime? " + MyInteger.isPrime(15));

char[] chars = {'3', '5', '3', '9'};
System.out.println(MyInteger.parseInt(chars));

String s = "3539";
System.out.println(MyInteger.parseInt(s));
int fib = MyInteger.fibonacci(50);

MyInteger n2 = new MyInteger(24);
System.out.println("n2 is odd? " + n2.isOdd());
System.out.println("45 is odd? " + MyInteger.isOdd(45));
System.out.println("n1 is equal to n2? " + n1.equals(n2));
System.out.println("n1 is equal to 5? " + n1.equals(5));
System.out.print("The Fibonacci number for 50 is" + MyInteger.fibonacci(50));
System.out.print(", and the result is palindrome:" + MyInteger.fibonacci(50).isPalindrome());

}
}

Wrote myself

public class MyInteger{
int value;

MyInteger(int newValue) {
value = newValue;
}

public int getValue() {
return value;
}

public boolean isEven() {
if (value % 2 == 0)
return true;
return false;
}

public boolean isOdd() {
if (value % 2 != 0)
return true;
return false;
}

public boolean isPrime() {
int factor = 0;
for (factor = 2; factor <= value / 2; factor++) {
if (value % factor != 0)
return true;
}
return false;
}

public static boolean isEven(int value) {
if (value % 2 == 0)
return true;
return false;
}

public static boolean isOdd(int value) {
if (value % 2 != 0)
return true;
return false;
}

public static boolean isPrime(int value) {
return isPrime(value);
}

public static boolean isEven(MyInteger myInt) {
return MyInteger.isEven(myInt.getValue());
}

public static boolean isOdd(MyInteger myInt) {
return MyInteger.isOdd(myInt.getValue());
}

public static boolean isPrime(MyInteger myInt) {
return myInt.isPrime();
}

public boolean equals(int intValue) {
return value == intValue;
}

public boolean equals(MyInteger myInt) {
return equals(myInt.getValue());
}
char [] digits = { '1', '2', '3'};
public static int parseInt(char[]digits) {
return Integer.parseInt(new String (digits));
}

public static int parseInt(String s) {
return Integer.parseInt(s);
}

public static int fibonacci(int n){
if ((n == 0) || (n == 1))
return n;
else
return fibonacci(n-2) + fibonacci(n-1);
}

public static boolean isPalindrome(String s) {
if (s.length() == 0 || s.length() == 1)
return true;
if (s.charAt(0) == s.charAt(s.length() - 1))
return isPalindrome(s.substring(1, s.length() - 1));
return false;
}
}

[kenson02]

here is the line with the problem
System.out.print(", and the result is palindrome:" + MyInteger.fibonacci(50).isPalindrome());

[Fubarable]

I don't see any isPalindrome method that allows for no parameters since there appears to be only one method, and it takes a String parameter. I suggest that you convert your int into a String, perhaps by using String.valueOf(...) and then pass this into the isPalindrome method.