# Thread: Code to determine how many elements of a givine infinite series are required to

1. Member Join Date
Oct 2011
Posts
5
Rep Power
0

## Code to determine how many elements of a givine infinite series are required to

find the value of pi, accurate to 5 decimal places?

Sorry the title got cut off. If not the code I'd appreciate a step by step explanation of how to do this problem.

Here it is:

Write a java project (Application) with just a driver class. This class should have a default constructor and a main method which calls it.

This project should determine how many elements of the infinite series shown below are required to find the value of pi, accurate to 5 decimal places.

pi / 4 = 1 - 1 / 3 + 1 / 5 - 1 / 7 + 1 / 9 - 1 / 11 + ...

You must use the following constant

private static final double PI = 3.14159;

and your program must use a do loop.

Your output should look like this:

Value of pi = 3.14159

Number of elements of the series = 130657

The value of pi is not the value of the constant, instead it is the value of the series rounded to 5 places.  Reply With Quote

2. ## Re: Code to determine how many elements of a givine infinite series are required to

First write a bit of code that creates the series 1/1-1/3+1/5-1/7 ... and work from there (the numerator flips between 1 and -1 while the deniminator takes the values 1, 3, 5, 7 ...).

kind regards,

Jos  Reply With Quote

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•