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Thread: Output a Two Decimal Value
 07172011, 11:26 AM #1Member
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Output a Two Decimal Value
It's suppose to display 12.50 but instead it's displaying 0.0
Java Code:import java.io.*; public class InputOutput { public static void main(String[] args) { String base=""; String height=""; BufferedReader input = new BufferedReader(new InputStreamReader(System.in)); try { System.out.print("Input base value = "); base = input.readLine(); System.out.print("Input height value = "); height = input.readLine(); } catch(IOException e) { System.out.print("Error"); } float area = 1/2*(Integer.parseInt(base)* Integer.parseInt(height)); System.out.println("The Area of the right triangle is "+ area); } }
 07172011, 11:41 AM #2
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Integer division (as in 1/2) chops of the entire fractional part of the quotient, so 1/2 == 0. Either multiply by 0.5 or do the division using floating point numbers, as in 1.0/2.0
kind regards,
JosBuild a wall around Donald Trump; I'll pay for it.
 07172011, 11:46 AM #3Member
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But i need to use the formula 1/2*bh for computing for the area of the triangle. What should I change in the code?
 07172011, 11:48 AM #4
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 07172011, 11:58 AM #5Member
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no, i mean i still have to use 1/2 not 0.5
 07172011, 12:09 PM #6
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Please reread the entire text of the 2nd post in this thread: 2nd post
 07172011, 12:24 PM #8Member
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Both of these will work:
float area = (1f/2f) * (Integer.parseInt(base)* Integer.parseInt(height));
float area = (0.5f) * (Integer.parseInt(base)* Integer.parseInt(height));
The problem is (as JosAH says) is that 1/2 =0.0 (because they are assumed to be int literals) so you need to make them float literals to return 0.5 correctly.
Babbard
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