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Thread: Return smallest value
 06052011, 07:55 PM #1Member
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Return smallest value
Hi I have an error with my code but I do not know what it is, here are my codes:
Java Code:public class Q2 { public static void main(String[] args) { int[] numbers={1,2,4,5,10,100,2,22}; int mostSmall= find(numbers); System.out.println(mostSmall); } public static int find(int[] numbers){ int smallest=0; for(int i=0;i<numbers.length;i++){ if(numbers[i]<=numbers[i+1]){ smallest= numbers[i]; } else{ smallest= numbers[i+1]; } } return smallest; } }
 06052011, 08:16 PM #2
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Most readers here aren't psychic; I am so I knew an ArrayIndexOutOfBounds error was thrown. Suppose your array length is 10; variable i goes from 0 to 9 (inclusive) but you are trying to access numbers[9+1] which goes kaboom. You have to fix that. b.t.w. you don't have to compare two consecutive numbers in the array to find the smallest number in the array.
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JosBuild a wall around Donald Trump; I'll pay for it.
 06052011, 08:49 PM #3Member
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Java Code:import java.math.*; public class Q2 { public static void main(String[] args) { int[] numbers={1,2,4,5,10,100,2,22}; int mostSmall= find(numbers); System.out.println(mostSmall); } public static int find(int[] numbers){ int smallest=0; for(int i=0;i<numbers.length;i++){ smallest= Math.min(numbers[7], numbers[i]); } return smallest; } }
 06052011, 08:51 PM #4Member
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Thanks for the tips.
 06052011, 09:25 PM #5
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 06062011, 04:29 PM #6Member
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It means comparing all the numbers in the array with the last number of the array to get the smallest value. Why do you ask?
 06062011, 04:52 PM #7
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 06062011, 04:57 PM #8Member
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Well based on my question paper(college), yeah this particular question contains only eight numbers. But I get what you mean :)
 06062011, 07:11 PM #9
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