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 03152011, 03:50 PM #1Member
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binary search...multiple datatypes?
I've seen a lot of examples of binary search functions, but can't find an example that allows for the use of multiple data types.
Would it be possible to have a binary search that allows for both integer and strings?
Thanks!
Here is one example I found that allows for integers:
Java Code:public class BinarySearch2 { public static final int NOT_FOUND = 1; /** * Performs the standard binary search * using two comparisons per level. * @return index where item is found, or NOT_FOUND. */ public static int binarySearch2( Comparable [ ] a, Comparable x ) { int low = 0; int high = a.length  1; int mid; while( low <= high ) { mid = ( low + high ) / 2; if( a[ mid ].compareTo( x ) < 0 ) low = mid + 1; else if( a[ mid ].compareTo( x ) > 0 ) high = mid  1; else return mid; } return NOT_FOUND; // NOT_FOUND = 1 } // Test program public static void main( String [ ] args ) { int SIZE = 8; Comparable [ ] a = new Integer [ SIZE ]; for( int i = 0; i < SIZE; i++ ) a[ i ] = new Integer( i * 2 ); for( int i = 0; i < SIZE * 2; i++ ) System.out.println( "Found " + i + " at " + binarySearch2( a, new Integer( i ) ) ); } }
 03152011, 04:06 PM #2
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Sure you can do that; you have to define the order between Integers and Strings, say all Integers are less than Strings. Use a Comparator<Object> to do the job. If it has to compare two objects that don't have the same type return 1 if it compares an Integer and a String, +1 if it compares a String and an Integer; otherwise it compares two things of the same type; compare the two objects as usual.
kind regards,
JosBuild a wall around Donald Trump; I'll pay for it.
 03152011, 04:32 PM #3Member
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I tried using generics like this:
Java Code:public int searchBinary3(T value, int val1, int val2, T[] a)
Thanks!
 03152011, 05:08 PM #4
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I don't understand what you're trying to do there; You can only compare Objects (Strings or Integers) or primitives (ints etc.) You need a simple compareTo(Object a, Object b) method that compares Strings and/or Integers, just as I described in my first reply. Leave out those generics; you don't need them
kind regards,
JosBuild a wall around Donald Trump; I'll pay for it.
 03152011, 06:56 PM #5Member
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Oh ok...but I thought with newer Java, you should use generics?
 03152011, 07:32 PM #6Member
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Another thing...generics or not...how can the same code compare the contents of both string and integer arrays?
Thanks!
 03152011, 08:07 PM #7
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 03152011, 08:20 PM #8Member
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I need to loop through an array, and check to see if certain items are in the array.
But the array could be integer or string...I got it to work with integers like this, but it won't work with strings:
Java Code:public int SearchArray(T[] a, T index, int low, int high) { result = 0; while (low <= high) { mid = (low + high) / 2; result = mid; if (a[mid].compareTo(index) < 0) low = mid + 1; else if (a[mid].compareTo(key) > 0) high = mid  1; else return mid; } return 1; }
 03152011, 09:03 PM #9
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As I wrote before: you have to write your own compareTo( ... ) method; something like this:
Java Code:int compareTo(Object a, Object b) { if ((a instanceof Integer) == (b instanceof String)) if (a instanceof Integer) return 1; else return 1; if (a instanceof Integer) return ((Integer)a).compareTo((Integer)b); else return ((String)a).compareTo((String)b); }
JosBuild a wall around Donald Trump; I'll pay for it.
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