Calculate the day of the week for a particular date

I have to write this program to show what day of week you were born i wrote this code but i don't know what i have to do after :( :mad::confused:

• You will be using the JOptionPane object and the .showInputDialog method to prompt for user input. Prompt the user for a String object that represents a date in the mm/dd/yyyy format such as: 04/24/1982.


public class DayName
{

public static void main (String[]args){
// These are integer valuse
int iMonth=0;
int iDay=0;
int iYear=0;
int iCenturyYear =0;

// These are string values
String sDay;
String sMonth;
String sYear;
String sCenturyYear;

// Let the user to input their Date of Birth
sDay = JOptionPane.showInputDialog("Enter the day of your Birthday: ");
sMonth = JOptionPane.showInputDialog("Enter the month of your birthday: ");
sYear = JOptionPane.showInputDialog("Enter the month of your birthday: ");

// Convert string to integers
iMonth = Integer.parseInt(sMonth);
iDay = Integer.parseInt(sDay);
iYear = Integer.parseInt(sYear);
iCenturyYear=Integer.parseInt(sCenturyYear);


JOptionPane.showInputDialog("Enter the birth date (mm/dd/yyyy): ");

}// end main
}// end of the DayName class

Are you allowed to use the java date class? If so I believe this can help you accomplish the task, try googling the java date API, it may be date format.

Technical Approach:
You can use the Java if samples on Blackboard as a basis or the examples from the book.

• You will be using the JOptionPane object and the .showInputDialog method to prompt for user input. Prompt the user for a String object that represents a date in the mm/dd/yyyy format such as: 04/24/1982.
• Use the String object’s methods to extract out these values and convert them to primitive integers:
o iDay (in our example it would be 24)
o iMonth (in our example it would be 04)
o iCenturyYear (in our example it would be 1982)
o iYear (in our example it would be 82)
• Write the if logic to determine if the year is a leap year. This can be accomplished as follows:
o If the year is divisible by 4 with no remainder and the year is divisible by 100
o Or the year is divisible by 400 with no remainder.
o Use a Boolean called bIsLeapYear to indicate if the years in a leap year.
• Write a Java if…else if logic to determine the Centuries Code for the iCenturyYear variable. Use the table below to find the value, in our example 1982 would be 0:
o 1700–1799 4
o 1800–1899 2
o 1900–1999 0
o 2000–2099 6
o 2100–2199 4
o 2200–2299 2
o 2300–2399 0
o 2400–2499 6
o 2500–2599 4
o 2600–2699 2


• Write a Java if…else if logic to determine the Months Code for the iMonth variable. Use the table below to find the value, in our example 04 would be 6:
o January 0 (if a leap year use 6 use bIsLeapYear variable to check)
o February 3 (if a leap year 2 use bIsLeapYear variable to check)
o March 3
o April 6
o May 1
o June 4
o July 6
o August 2
o September 5
o October 0
o November 3
o December 5
• Once you have extracted the different values of the date and you have determined the Centuries Code and the Month Code do this calculation:
o The Centuries Code for 11/24/1982 should be: 0
o Note the last two digits of the iYear variable: 82
o Divide the 82 by 4: 82/4 = 20.5 and drop the fractional part: 20
o The Month Code for 04 in the iMonth variable should be: 6
o Add all numbers from steps 1–4 to the day of the month iDay (in this case, 24): 0+82+20+6+24=132.
o Modulus divide the sum from step 5 by 7 and find the remainder: 132/7=18 remainder 6
o Find the remainder in the days name table below using a Java switch statement: 6=Saturday:
 0 Sunday
 1 Monday
 2 Tuesday
 3 Wednesday
 4 Thursday
 5 Friday
 6 Saturday
• Once you have determined the day of week use the JOptionPane object’s. showMessageDialog method to show the date that was inputted and the Day Name you computed.
• Make sure to use Hungarian notation and ample comments. Your code should contain your name, date, Programming Assignment 6 and some general comments as to what the purpose of the code is.
• Upload the Java source code and the compiled class to blackboard by the due date.

Testing Plan:
Date Result
4/24/1982 Saturday
09/18/1783 Thursday
06/08/1998 Monday
06/19/2054 Friday
02/29/1996 Thursday
Your Birthday ?

This is the whole thing that he gave us

Alright, it is pretty confusing if you read it all at once but just re read it a few times. The questions gives you a step by step on how to do it, just follow that description precisely. Read the questions a few times and get as deep an understanding as you possibly can.

I have been trying it for so long if i could of i would of done it

Well you are not trying very hard.

Your instructions say to get user input in the format of mm/dd/YYY. That is ONE input and yet you have this:

Code:

---

// Let the user to input their Date of Birth
sDay = JOptionPane.showInputDialog("Enter the day of your Birthday: ");
sMonth = JOptionPane.showInputDialog("Enter the month of your birthday: ");
sYear = JOptionPane.showInputDialog("Enter the month of your birthday: ");

---

The instructions spell it out very comprehensively in a step by step manner. Simply follow the steps. Do not move onto the next step until you have coded and fully tested each step.

// This is what i have done


import javax.swing.*;
import java.util.Calendar;
import java.util.Date;

public class DayName
{

public static void main (String[]args){
// These are integer valuse
int iMonth=0;
int iDay=0;
int iYear=0;
int iCenturyYear =0;
int icentCode = 0;
int iMonCode = 0;

// These are string values
String sDay = "";
String sMonth = "";
String sYear = "";
String sCenturyYear = "";

// This is a boolean value
boolean bIsLeapYear = false;

// Let the user to input their Date of Birth
String sGetDate = JOptionPane.showInputDialog("Enter the birth date in the format (mm/dd/yyyy): ");

// Convert string to integers

int icount = 0;

for (int n = 0; n < 2; n++)
{

sDay += sGetDate.charAt(n);

icount++;


}//end for


for (int n = 3; n < 5; n++)
{

sMonth += sGetDate.charAt(n);

icount++;


}//end for

for (int n = 8; n < 10; n++)
{

sYear += sGetDate.charAt(n);

icount++;


}//end for

for (int n = 6; n < 10; n++)
{

sCenturyYear += sGetDate.charAt(n);

icount++;


}//end for

//converting user input without slash '/' to interger
iDay = Integer.parseInt(sDay);
iMonth = Integer.parseInt(sMonth);
iCenturyYear = Integer.parseInt(sCenturyYear);
iYear = Integer.parseInt(sYear);

/*if()
{
boolean bIsLeapYear =
}*/

if (iCenturyYear >= 1700 || iCenturyYear <= 1799)
{
icentCode = 4;
}//end iCenturyYear range 1700 - 1799
else if (iCenturyYear >= 1800 || iCenturyYear <= 1899)
{
icentCode = 2;
}//end iCenturyYear range 1800 - 1899
else if (iCenturyYear >= 1900 || iCenturyYear <= 1999)
{
icentCode = 0;
}//end iCenturyYear range 1900 - 1999
else if (iCenturyYear >= 2000 || iCenturyYear <= 2099)
{
icentCode = 2;
}//end iCenturyYear range 2000 - 2099
else if (iCenturyYear >= 2100 || iCenturyYear <= 2199)
{
icentCode = 6;
}//end iCenturyYear range 2100 - 2199
else if (iCenturyYear >= 2200 || iCenturyYear <= 2299)
{
icentCode = 4;
}//end iCenturyYear range 2200 - 2299
else if (iCenturyYear >= 2300 || iCenturyYear <= 2399)
{
icentCode = 2;
}//end iCenturyYear range 2300 - 2399
else if (iCenturyYear >= 2400 || iCenturyYear <= 2499)
{
icentCode = 0;
}//end iCenturyYear range 2400 - 2499
else if (iCenturyYear >= 2500 || iCenturyYear <= 2599)
{
icentCode = 6;
}//end iCenturyYear range 2500 - 2599
else if (iCenturyYear >= 2600 || iCenturyYear <= 2699)
{
icentCode = 4;
}//end iCenturyYear range 2600 - 2699

if (iMonth == January)
{
iMonCode = 0;
}//end January

if (iMonth == february)
{
iMonCode = 3;
}//end February

JOptionPane.showMessageDialog(null, sDay + " " + sMonth + " " + sCenturyYear + " " + sYear,"Get Date is: GetDate", JOptionPane.INFORMATION_MESSAGE);




}// end main
}// end of the DayName class

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