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  1. #1
    Nel is offline Member
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    Mar 2011
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    Smile Palindrome program help

    Hey guys, so I'm brand new to java and this forum. This is my first post. I seem to be having difficulty with this program. I know I have a logic error in my code, but I can't seem to locate it. The program is supposed to take any series of characters, including numbers and test if it is a palindrome. If any symbols !@#$%^&* are entered, they are to be ignored. (So 1@23!43#2-1 is a palindrome.) It works fine for numbers, but it says every string input is a palindrome. I havnt gotten far into the book, so my tools are limited to basic string manipulations and basic loop structures. Please help by giving only suggestions or hints; no code as I am trying to learn =) Thanks! (Also, how do I put code into the post without Copy/Paste and manual formatting? I couldn't find/understand in the FAQ.)

    Java Code:
    import java.util.Scanner;
    public class Palindrome 
         public static void main(String[]args)
    	    Scanner keyboard = new Scanner(;
    	    String userStr, newStr, compareStr;
    	    int right, left;
    	    newStr = "";
    	    compareStr = "";
                     System.out.print("Please enter any sequences of characters: ");
    	    userStr = keyboard.nextLine();
    	    newStr = userStr.toLowerCase();
    	    compareStr = newStr.trim();
    	    compareStr =  compareStr.replaceAll("\\D", "");
                     right = compareStr.length() - 1;
    	    left = 0;
    	       while(left<right && left!=right)
    		          System.out.print(userStr + " is not a Palindrome.");
    	System.out.print(userStr + " is a Palindrome.");

  2. #2
    Junky's Avatar
    Junky is offline Grand Poobah
    Join Date
    Jan 2011
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    Java Code:
    compareStr =  compareStr.replaceAll("\\D", "");
    System.out.println(">" + compareStr + "<"); //add this line to get your answer
    By the way
    Java Code:
    while(left<right && left!=right)
    the second condition is pointless if the first condition is true then the second MUST be true.

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