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  1. #1
    AcousticBruce is offline Senior Member
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    Dec 2010
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    Default Understanding String vs new String()

    This is odd, but there must be a reason.

    This code returns "Does NOT"
    Java Code:
            String str1 = new String("String One");
            String str2 = new String("String One");
            if (str1 == str2) {
            } else {
                System.out.println("Does NOT");

    This code returns "Equals"
    Java Code:
            String str1 = "String One";
            String str2 = "String One";
            if (str1 == str2) {
            } else {
                System.out.println("Does NOT";

  2. #2
    Fubarable's Avatar
    Fubarable is offline Moderator
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    Jun 2008
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    == tests to see if the object referred to by one variable is the same object as that referred to by the other variable, and with Strings (and most other objects), you really don't care about this. What you want to know instead is are strings themselves, the characters, order of characters and case the same for one String vs another, and this is where equals(...) and equalsIgnoreCase(...) come in.

    You'll want to read up on the String pool too to find out why you're getting different results in your two cases above.

  3. #3
    jomypgeorge is offline Member
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    May 2010
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    when we assign a value to string variable compiler checks if it is already used in the same program. if it is used it assign same object to reference

    String str1 = "hello";
    String str2 = "hello;

    is equivalent to

    String str1, str2;
    str1 = "hello";
    str2 = str1;
    both str1,str2 points to same object.

    but in the case of new operator it create new object of string with same value.

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