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 08172010, 10:58 AM #1Member
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 08172010, 11:33 AM #2
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 08172010, 11:58 AM #3Member
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OK, I understood explanation. Thank you very much for that.
I don't know how to code that. I have drawn a shape in paintComponent method like this:
Java Code:g.fillOval(50, 50, 20, 20);
Best regards,
Milica
 08172010, 01:55 PM #4
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Assume the circle's midpoint is the origin (0, 0); the midpoint of the ball makes a circular movement over a cirlce with radius Rr, so every point can be described as x= (Rr)*cos(phi), y= (Rr)*sin(phi) for any value of phi in [0, 2*PI).
You don't want to know where the midpoint of the ball is, you want to know the top left position of the bounding square; if the midpoint of the ball is at position (x, y) (see above) then the top left point of the bounding rectangle is at position (x(Rr), y(Rr))
The variable phi serves as a loop counter.
kind regards,
Jos
 08172010, 02:25 PM #5Member
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Thank you very much for this explanation.
Should I use timer for this moving (to put that loop's code in it) or something similar?Last edited by mneskovic; 08172010 at 02:28 PM.
 08172010, 02:53 PM #6
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 08172010, 03:08 PM #7Member
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Can you explain me how to put timer in thread?
I have been making timers like this:
Java Code:timer1 = new Timer(500, new ActionListener() { public void actionPerformed(ActionEvent e) { x1++; PanelName.this.repaint(); }});
I would like to stop delays in timer, but if I put 0 instead of 500 it doesn't work well.
How to do that?
 08172010, 03:16 PM #8
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 08172010, 04:05 PM #9Member
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