Could you plese explain somebody how come output of these codes.

[moonlanka]

class prog5
{
public static void main(String[]args)
{
char a='N';
byte b = 125;
short c=32767;

System.out.println("a="+a);
--a;
System.out.println("a="+a);
System.out.println("b="+b);
++b;
System.out.println("b="+b);
System.out.println("c="+c);
++c;
System.out.println("c="+c);
++b;
System.out.println("b="+b);
++b;
System.out.println("b="+b);
System.out.println("result1="+b%c);
System.out.println("result2="+b/c);

}
}

[r035198x]

Which output don't you understand?

[Norm]

Read up on arithmetic operators and integer arithmetic.

[JosAH]

class prog5
{
public static void main(String[]args)
{
char a='N';
byte b = 125;
short c=32767;

System.out.println("a="+a);
--a;
System.out.println("a="+a);
System.out.println("b="+b);
++b;
System.out.println("b="+b);
System.out.println("c="+c);
++c;
System.out.println("c="+c);
++b;
System.out.println("b="+b);
++b;
System.out.println("b="+b);
System.out.println("result1="+b%c);
System.out.println("result2="+b/c);

}
}

The output comes from all those System.out.println( ... ) calls.

kind regards,

Jos

[moonlanka]

Output for this program :
a=N
a=M
b=125
b=126
c=32767
c=-32768
b=127
b=-128
result1=-128
result2=0



So want to know , How come result c=-32768 and result1 and result2

[r035198x]

Ask yourself what the maximum value of a short it. Then ask yourself what happens when this value is exceeded. Read your text book if you can't answer any of those questions.

[alacn]

Output for this program :
a=N
a=M
b=125
b=126
c=32767
c=-32768
b=127
b=-128
result1=-128
result2=0



So want to know , How come result c=-32768 and result1 and result2

heres the answer

its to do with how the info is stored in binary. once you go above the higest amount, the most siognificant bit becomes a positive thus the overall value now gets represented in minus format.
Also if you were to add a large enough value to it, then the value you'd expect wouldnt fit in the allocated memory space, and the data would overflow into the next byte alongside it

Anways the system is called twos complement, read up on it here

Two's complement - Wikipedia, the free encyclopedia

[moonlanka]

Thanks all experts, still I have problem in result1 and result2 in my program. I know the symbol % is remain and / division.

c=-32768
b=-128

System.out.println("result1="+b%c);
System.out.println("result2="+b/c);

How is comes like,
result1=-128
result2=0

[j2me64]

System.out.println("result1="+b%c);
System.out.println("result2="+b/c);

as you can see the result2 of b/c is 0, so the remain of result1 must be -128.