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 12282009, 03:26 PM #1Member
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Array Index Out Of Bounds and Problem in Assigning Values
Java Code:public class Ch6Exercise8 { public static void main(String[] args) { int[] divisors = new int[0]; int number = 7, divisibilityCount = 0; for (int x = 1; x <= number; x++) { if (number % x == 0) { divisibilityCount++; divisors = new int[divisibilityCount]; } for (int i = 0; i <= divisors.length  1; i++) { if (divisors[i] == 0) { divisors[i] = x; } else { divisors[i + 1] = x; } } } for (int x = 0; x <= divisors.length  1; x++) { System.out.println(divisors[x]); } } }
please help me here..
what i want in this program is that i want to determine if a number is a prime number(im okay with this part),
but im having problem with the ff:
1.) store it in an integer[] array
2.) the length of an array WILL ONLY DEPEND on the number of the values.
ex: (ofcourse prime numbers are only divisible by 1 and itself) ,
so i want to STORE those values in an array.
but as the case have said, THE LENGTH OF THE ARRAY WILL ONLY
DEPEND O N THE number (i.e Length) of the values. :confused:
 12282009, 07:54 PM #2
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Check your loop for x == 2; no new array will be created and the first value is not equal to zero. I don't know what you want to do exactly but may I suggest you use a List<Integer> for all divisors instead?
kind regards,
Jos
 12282009, 08:14 PM #3
Your first Exception is because of the inner loop:
If your last number (where i == devisors.length1) is not zero you jump to the else branch and try to access the array with [i+1] where i+1 is then greater than the bounds of an array
it also very strage why you do that and maybe wrong.
As for your assignment:
Yes, you are right the borders depends on the given number but the number of devisors is limited: it is easy to see that the highest number of devisors would be n/2; namely the the maxmial amount of the smallest devisor: 2
(of course this is not optimal solution)
Also there are two approaches, depending on what you want to achieve.
If you want to do a Primality test then the Sieve of Eratosthenes is a one easy way.
If you want to do factorization look into integer factorization but there is no easy way do do it ;)"There is no foolproof thing; fools are too smart."
"Why can't you solve my Problem ?"
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