Simple IO problem

[aamp]

Hello,

I'm trying to read utf string from bytearray like this:

byteInput = new ByteArrayInputStream(data);
dataInput = new DataInputStream(byteInput);

string that lies in dataEvent data is 2048 symbols length.

dataInput.available() gives me 2050 and it means first 2 bytes on byte array are the length of utf string. I read it with dataInput().readShort() and I get 2048 wich is correct. But when I try to read the string with readUTF() (not reading the length, i mean from beggining of stream) i get EOFException. If the string that lies in my bytearray is like 1024 or less in length I dont get EOFException, my string is read ok:

byteInput = new ByteArrayInputStream(data); // there is 2048-length UTF 
string in data (bytearray)
dataInput = new DataInputStream(byteInput);
String s = dataInput.readUTF(); // throws EOFException
//-------------------------------------------------------------
byteInput = new ByteArrayInputStream(data); // there is 1024-length UTF string in data (bytearray)
dataInput = new DataInputStream(byteInput);
String s = dataInput.readUTF(); // works

Why a length of 2048 isnt working?

[Nicholas Jordan]

First two bytes are normally "byte order mark" ( BOM ) which sounds like what the first two bytes are rather than length of the string.

[aamp]

A quote from Java reference:
First, two bytes are written to the output stream as if by the writeShort method giving the number of bytes to follow.

But that doesn't change anything. Why does it throw EOFException when I try to read somewhat long string? I mean, dataInput.available() gives me an exact length of what I need to read, though it just threws up.

P.S. I get this string throught java.nio TCP socket channel, maybe there any length limitations or the data is transferred in portions?