I need help on solving an exercise from school

[dekelm12]

Hi,
I began my journey in Java a few months ago so I'm a beginner.
I learn it in my school.
Anyway I got an assignment that I need help with.
How do I do the following assignment?

Write a code that inputs 10 numbers into a one-dimensional alignment - a.
The code will define a new alignment - b which is made of the alignment a in the power of 2.
The code will define an alignment - c, which is made of the product of the number in alignment - a with the numbers in alignment - b.
The code will output in the first row the numbers of alignment - a.
In the second row, the numbers of alignment - b will be outputted.
In the third row, the numbers of alignment - c will be outputted.

That's it :) Thanks!

import java.util.Scanner;
public class daf167
{
  public static void main(String[]args)
  {
    Scanner in= new Scanner(System.in);
    int[] a=new int[10];
    int[] b=new int[10];
    int[] c=new int[10];
    int i;
    for(i=0;i<=9;i++)
    {
      System.out.println("Enter a number");
    a[i]=in.nextInt();
    for(i=0;i<=9;i++)
      b[i]=a[i]*a[i];
    for(i=0;i<=9;i++)
      c[i]=a[i]*b[i]
    }
    System.out.println("The first row - a is" +a[i]);
    System.out.println("The second row - b is" +b[i]);
    System.out.println("The third row - c is" +c[i]);
  }
}

This is what I've done. What's wrong with it? It doesn't work.

By the way, do you have any tips for Java beginners? :)

[travishein]

well, let's look at what an input and output might look like.

enter 10 numbers
4 5 1 6 3 8 0 9 13 11

alignment a: 4 5 1 6 3 8 0 9 13 11
alignment b: 16 25 1 36 9 64 0 81 169 121
alignment c: 64 125 1 216 27 512 0 729 1331

note that having row b product with row a is really just row a ^ 3. but what ever.

so I am thinking of 3 arrays of integers, or double types.

using the "Scanner" class to read input from the user, and invoking nextInt() to parse the tokens entered on the line into the first array a[], using a for() loop probably.

then in a second for() loop, perform the a[i] * a[i] operation, storing into b[i].

then in a third for() loop, perform c[i] = a[i] * b[i];

then in a fourth for() loop, print out the contents of a into a line

a fifth for() loop to print out the contents of line b

a sixth for() loop to print out the contents of line c

well, all the looping purely for academic clarity here;

[travishein]

extra points for style using the StringBuilder to construct outputs and using tab characters to format into pretty columns.

[dekelm12]

import java.util.Scanner;
public class daf167
{
  public static void main(String[]args)
  {
    int[] a=new int[10];
    int[] b=new int[10];
    int[] c=new int[10];
    int i;
    for(i=0;i<=9;i++)
    {
      System.out.println("Enter a number");
    a[i]=in.nextInt();
    for(i=0;i<=9;i++)
      b[i]=a[i]*a[i];
    for(i=0;i<=9;i++)
      c[i]=a[i]*b[i]
    }
    System.out.println("The first row - a is" +a[i]);
    System.out.println("The second row - b is" +b[i]);
    System.out.println("The third row - c is" +c[i]);
  }
}

That is what I've done, what's wrong with it? It doesn't work.

[dekelm12]

Never mind guys, I managed to solve it by myself :)