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Thread: java floating point comparison
 03012009, 12:45 AM #1Member
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java floating point comparison
I am doing numerical analysis in Java. Due to all the arithmetic including the use of rounding functions, I often end up with floating point numbers such as 29.400000000000002 or 0.00000000001. I often need to compare such numbers for equality which fails because of the error induced.
How do I compare these numbers? I tried using an epsilon such as
if (Math.abs(ab) <= EPISLON) { }
but the problem is that the EPSILON is variable and does not always work..
thank you,
Sam
 03012009, 01:12 AM #2Moderator
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I often need to compare such numbers for equality which fails because of the error induced.
("Error" suggests that there is something wrong. And there isn't.)
but the problem is that the EPSILON is variable and does not always work.
Sometimes all we want of "a==b" is that the quantities are within some small (fixed) tolerance. So we declare EPSILON as some static final amount and use it as you suggest.
Other times that won't do. For instance the acceptable closeness might be a relative value: a certain proportion of the given values. We might express that with
Java Code:static final int FACTOR = ... if(Math.abs(ab) <= Math.abs(a+b)/FACTOR) { ...
It would seem to depend on the details of what you are trying to do: ie on what "doesn't work" means in this case.Last edited by pbrockway2; 03012009 at 01:15 AM. Reason: typo
 03012009, 05:30 AM #3
Your question is not really a Java question, the same topic comes up in all languages that use floating point. Your "problem" is not a problem, its a feature of how floating point works on computers.
Your "EPISLON" comment about it being a variable is not technically correct, its only a variable if you write your code to have it as a variable. But variable or constant, that's not the solution.
@pbrockway2's hints are in the right direction, but you really need to engineer the numerical analysis of your algorithm. You should google for "numerical analysis". The proper answer depends on your problem domain, and what kinds of calculations are being done.
 03022009, 06:31 AM #4Senior Member
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Numerical analysis requires that you keep track of the maximum possible error your self, and then compare consider all numbers that are within that error bound as equivalent.
That's hard.
The easier approach, is to use integer math instead of floating point math. If a long does not give you enough significant digits, you can use a BigInteger.
 03032009, 06:44 AM #5
Using BigInteger is not practical for a lot of things. Its domain specific, but for example, calculating correlation coefficients requires floating point. As does much of engineering.
BigInteger is not a solution to the problem, its designed for exactly what its name is, really big integers.
 03032009, 07:02 AM #6Senior Member
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 03032009, 04:11 PM #7
You can use BigDecimal if you need exact representation and calculation of large values with decimal places. However, that's generally reserved for financial applications.
I don't understand why you say your solution doesn't work. First, if you need more precision, use double instead of float. Second, so what if you have a field named epsilon? (Don't use all upper case unless this field is declared static final, which makes it a constant.) You can write a utility class that has a method
public static boolean equalTo(double pValue1, double pValue2, double pEpsilon) {
return pValue1 >= pValue2 ? (pValue1  pValue2 <= pEpsilon) : (pValue2  pValue1 <= pEpsilon);
}
This allows you specify the value of epsilon.
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