Hello, what do you want to do? , if it is to parse xml you can work with
DOM or
SAX being this much more fast since using DOM to parse this load the document in memory and creates an object from, example of
DOM:
<?xml version="1.0"?>
<company>
<employee>
<firstname>Tom</firstname>
<lastname>Cruise</lastname>
</employee>
<employee>
<firstname>Paul</firstname>
<lastname>Enderson</lastname>
</employee>
<employee>
<firstname>George</firstname>
<lastname>Bush</lastname>
</employee>
</company>
import java.io.File;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
public class XMLReader {
public static void main(String argv []) {
try {
File file = new File("c:\\MyXMLFile.xml" );
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(file);
doc.getDocumentElement().normalize();
System.out.println("Root element " + doc.getDocumentElement ().getNodeName());
NodeList nodeLst = doc.getElementsByTagName("employee") ;
System.out.println("Information of all employees") ;
for (int s = 0 ; s < nodeLst.getLength(); s++) {
Node fstNode = nodeLst.item(s);
if (fstNode.getNodeType() == Node.ELEMENT_NODE ) {
Element fstElmnt = (Element) fstNode;
NodeList fstNmElmntLst = fstElmnt.getElementsByTagName("firstname" );
Element fstNmElmnt = (Element) fstNmElmntLst.item (0);
NodeList fstNm = fstNmElmnt.getChildNodes();
System.out.println("First Name : " + ((Node) fstNm.item(0)) .getNodeValue());
NodeList lstNmElmntLst = fstElmnt.getElementsByTagName("lastname") ;
Element lstNmElmnt = (Element) lstNmElmntLst.item (0);
NodeList lstNm = lstNmElmnt.getChildNodes();
System.out.println("Last Name : " + (( Node) lstNm.item(0)) .getNodeValue());
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
}
if you want to continue investigating there are very interesting things like api of
XPATH for java (something like query, so that you do not have to cross xml complete in java)
The Java XPath API
also this
JDOM Simplify XML programming with JDOM
and here is the articulate where they speak of how turning from
SAX to
DOM
Tip: Converting from SAX
Marcus