get binary value

[rushenas]

Hi all
Consider that I have a string in hex like this:

3020058020C00004

Now I wanna convert it to binary, then I wanna have each digit single. For example, binary value for above string is:

11000000100000000001011000000000100000110000000000000000000100

And I wanna have

1
1
0
0
0
0
0
0
1
0
0
0
0
0
0
0
0
0
0
1
0
1
1
0
0
0
0
0
0
0
0
0
1
0
0
0
0
0
1
1
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
1
0
0

How can I achieve this?

[danielstoner]

You can use:

// Long: static long parseLong(String s, int radix)
long l = Long.parseLong("3020058020C00004", 16);

// Long: static String toBinaryString(long i)
String b = Long.toBinaryString(l);

// String: char charAt(int index)
for (int i = 0; i < b.length(); i++)
{
    System.out.println(b.charAt(i));
}

to parse the input String to a long and then to transform it into a binary string. In th end you display the digits one by one.

[Fubarable]

cross-posted in the Sun Java forums.