get binary value

Hi all
Consider that I have a string in hex like this:

Code:

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3020058020C00004

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Now I wanna convert it to binary, then I wanna have each digit single. For example, binary value for above string is:

Code:

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11000000100000000001011000000000100000110000000000000000000100

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And I wanna have

Code:

---

1
1
0
0
0
0
0
0
1
0
0
0
0
0
0
0
0
0
0
1
0
1
1
0
0
0
0
0
0
0
0
0
1
0
0
0
0
0
1
1
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
1
0
0

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How can I achieve this?

You can use:

Code:

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// Long: static long parseLong(String s, int radix)
long l = Long.parseLong("3020058020C00004", 16);

// Long: static String toBinaryString(long i)
String b = Long.toBinaryString(l);

// String: char charAt(int index)
for (int i = 0; i < b.length(); i++)
{
    System.out.println(b.charAt(i));
}

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to parse the input String to a long and then to transform it into a binary string. In th end you display the digits one by one.

cross-posted in the Sun Java forums.