[SOLVED] Cast string type to int type

GilaMonster · #1 (**permalink**) 06-13-2008, 02:12 AM

Hi all,

I am attempting to split a 6 digit numeric string into 2 seperate strings of 5 char's and 1 char respectively.

I am receiveing this compile error:

Quote:

TicketNumber.java:22: inconvertible types
found : java.lang.String
required: int
ticket1 = (int)ticketNumber1;
^
TicketNumber.java:26: inconvertible types
found : java.lang.String
required: int
ticket5 = (int)ticketNumber5;

Seem I cannot cast a string type to an integer type?

Full code below
Thanks
Winston

Code:

import javax.swing.JOptionPane;
public class TicketNumber
{
	public static void main(String[] args)
	{
		String ticketNumber, ticketNumber1, ticketNumber5;
		int ticket5, ticket1, seven = 7;
		
		//Get ticket number
			ticketNumber = JOptionPane.showInputDialog(null,
				"Please enter a 6 digit number", "Travel Tickets Company",
				JOptionPane.QUESTION_MESSAGE);
		
		//Get last digit of ticket number, convert to integer
			ticketNumber1 = ticketNumber.substring(5,1);
			ticket1 = (int)ticketNumber1;
		
		//Get first five digits of ticket number, convert to integer
			ticketNumber5 = ticketNumber.substring(1,5);
			ticket5 = (int)ticketNumber5;
			
		//Logic Test: Divide 5 Digit ticket number by 7. The remainder should equal the sixth digit previously truncated
			boolean isTestSuccessful = (ticket1 == (ticket5 % seven));
		
		//Output results
			JOptionPane.showMessageDialog(null, 
				"Original ticket # is: " + ticketNumber +
				"\nFive digit ticket number is: " + ticketNumber5 +
				"\nThe last digit is: " + ticketNumber1 +
				"\nDoes the five digit number divided by seven equal the last digit? " +
				"\n" + isTestSuccessful);
		System.exit(0);
	}
}

Nicholas Jordan · #2 (**permalink**) 06-13-2008, 02:35 AM

Without reading your code, you can get the character at any positon in a String object by calling .charAt(int position);

I will read your code momentarily, I am busy right now.

GilaMonster · #3 (**permalink**) 06-13-2008, 02:55 AM

Thanks Nicholas,

Using your example, how would I get a substring of 5 char's beginning at char 1?

How do I then cast from a 5 char string into a 5 digit integer?

Thanks much,
Winston

Fubarable · #4 (**permalink**) 06-13-2008, 04:03 AM

You can't "cast" a String to an int. Java just won't allow it. You can however parse the string with Integer.parseInt(yourString). Be sure to trap for number format exceptions here.

GilaMonster · #5 (**permalink**) 06-13-2008, 04:21 AM

Thanks Fubarable,

That did the job!
Thanks for your help
Final code below

Best regards,
Winston

Code:

import javax.swing.JOptionPane;
public class TicketNumber
{
	public static void main(String[] args)
	{
		String ticketNumber, ticketNumber1, ticketNumber5;
		int ticket5, ticket1, seven = 7;
		
		//Get ticket number
			ticketNumber = JOptionPane.showInputDialog(null,
				"Please enter a 6 digit number", "Travel Tickets Company",
				JOptionPane.QUESTION_MESSAGE);
		
		//Get last digit of ticket number, convert to integer
			ticketNumber1 = ticketNumber.substring(5);
			ticket1 = Integer.parseInt(ticketNumber1);
			
		//Get first five digits of ticket number, convert to integer
			ticketNumber5 = ticketNumber.substring(0,5);
			ticket5 = Integer.parseInt(ticketNumber5);
			
		//Logic Test: Divide 5 Digit ticket number by 7. The remainder should equal the sixth digit previously truncated
			boolean isTestSuccessful = (ticket1 == (ticket5 % seven));
		
		//Output reuslts
			JOptionPane.showMessageDialog(null, 
				"Original ticket # is: " + ticketNumber +
				"\nFive digit ticket number is: " + ticketNumber5 +
				"\nThe last digit is: " + ticketNumber1 +
				"\nIs the remainder of the five digit number divided by seven equal the last digit? " +
				"\n" + isTestSuccessful);
		System.exit(0);
	}
}