How to say if (odd)?

[frasifrasi]

I have an array of 8 numbers. I want to say that if the index of the array is odd, do something.
For example:
add up all numbers int he odd indexes:
array[1]+array[3]+array[5] ...

How would I code this--any suggestions?

[Fubarable]

cross-posted in the Sun Java forums.

[sukatoa]

not clear actually....

What's the purpose of adding up all the value from those elements if your question is to have a logical value that represents odd or not?

You may design a method that returns a logical value true/false with a parameter int value.....

Here is an example,

public static final boolean isOdd(int value){
      return (value%2)>0;
}

Then, use that for testing those elements if the value is an odd or not....

If satisfied, do the operation....

You may use simplified operator "+="

[Eranga]

Hope you are looking something like this.

    public static void main(String[] args) {
        // TODO code application logic here
        int[] number = new int[8];
        number[0] = 1;
        int sum  = 0;
        
    // Filled the array with some numbers
        for(int i = 1; i < number.length; i++) {
            number[i] = number[i - 1] * 2;
        }

    // Process
        for(int j = 0; j < number.length; j++) {
            if(j%2 != 0) {
                sum += number[j];
            }
        }
        
        System.out.println(sum);
    }

[frasifrasi]

^ Yes, very simple. Thank you for the insight.

[Eranga]

Did you solve this question. If so please mark it as solved.