How do I strip down integers for future manipulation?

[frasifrasi]

Ok, so here is the deal.

Part of an assignment is to take a long number like

1238398173987

and strip it down to
ints like 1 2 3 8 etc...

but we won't be using arrays since we did not learn this yet in class.

So my question is how would I separate the numbers?

Would using modulus do it? if so, would I have to declare all the individual ints?

I need to do this in order to then do various conditional statements to the integers and to add them up.

Suggestions are welcome, thank you.

[pao]

Hi here is one way you could do it, and the create Integers from the individual results. You would probably need some validation to make sure the character is actually a numeric value. Hope it gives you some ideas.

public class StringSplit {
    
    public static void main(String[] args) {
        int toBeSplit = 123456;
        String string = Integer.toString(toBeSplit);
        
        for(int i = 0; i < string.length(); i++) {
            Integer integer = new Integer( Integer.valueOf( new Character(string.charAt(i)).toString() ) );
            System.out.println("int = " + integer.intValue());
        }
    }
}

[sukatoa]

Same idea.... remove this admin....

[pao]

Hey sorry I was bored and just got home from work!

[sukatoa]

That's ok, i thought nobody gonna answer this thread at that moment.... My reply is just an algorithm of yours, so i removed it....

Usually, this kind of question needs a code, not an algo... :)

[pao]

I was just bored and waiting to go out, I thought it looked like a nice quick problem to solve and I never had to do that before, but it still looked like fun.

[Zosden]

If you wanted a fun way to do it just take powers of 10 from it.

[frasifrasi]

Thank you for the suggestions everyone.

[pao]

If you wanted a fun way to do it just take powers of 10 from it.

Hi can you a give java code snippet, that would be helpful.

[frasifrasi]

Yes, that would help. I tried doing it but all I got was the first number on the right, then the last TWO numbers on the right.

[pjm35@st-and.ac.uk]

Here's one, returns an integer array containing all the digits of an integer in order.

Probably could be better though.

public int[] longSplit(int toSplit){
		
		LinkedList<Integer> ret=new LinkedList<Integer>();
		
		int tens=10;
		int j=0;
		
		while(tens<toSplit*10){
			int prev=0;
			for(int k=0;k<j;k++){
				prev+=ret.get(k);
			}
			ret.add((toSplit%tens-prev)/(tens/10));
			tens*=10;
			j++;
		}
		
		
		int[] r=new int[ret.size()];
		for(int i=0;i<ret.size();i++){
			r[i]=ret.get(i);
		}
		
		return r;
		
	}

[frasifrasi]

That has got to be an easier way of doing this though.

[ferranb]

Another nice way:

    public int[] intToArray(int number) {
	    int size = (int) Math.ceil(Math.log10(number));
	    int[] digits = new int[size];
	    double aux = number;
	    for (int i=size-1 ; i>=0 ; i--)
	    {
	        digits[i] = (int) aux%10;
	        aux /= 10; 
	    }
	    return digits;
    }

To print the result:

        for (int d : intToArray(61235437))
            System.out.print(d);

Ferran