get exception name

[jithan]

hello friends,

i have to get a exception name ........ in the following example .......... pls help me......
java.lang.ArrayIndexOutOfBoundsException: 4
at exec.main(exec.java:7)

here i have to get exception name ..........

[pao]

Do you mean the class of the Exception? If you do then I can help a little, if you actually mean 'Name' then I don't know!

  try {
            if(true) {
                System.out.println("throwing exception");
                throw new ArrayIndexOutOfBoundsException("Example");
            }
        } catch (Exception e) {
                System.out.println("class = " + e.getClass().toString());
        }

This will get you the class of the Exception that was thrown, the output is:

init:
deps-jar:
compile-single:
run-single:
throwing exception
class = class java.lang.ArrayIndexOutOfBoundsException
BUILD SUCCESSFUL (total time: 0 seconds)

[DonCash]

I am confused as to what you want here.

ArrayIndexOutOfBoundsException

Is the name of the exception.

[jithan]

s exactly i have to get a class of the exception......... help me.....

[DonCash]

What pao posted should help you.

ArrayIndexOutOfBoundsException (Java 2 Platform SE v1.4.2)

[jithan]

thank q friends i got the result.........

[vinaytj]

s exactly i have to get a class of the exception......... help me.....

ArrayIndexOutOfBoundsException is itself only the class name of that exception.

i think you are passing values through command line in the program "exec".

if so , do like this
ex,,

Public static void main(String s[])
{
try{

write your code here,,,,,

}
catch(ArrayIndexOutOfBoundsException e)
{
System.out.println(e);
}

}// end of main



i hope it works,,,,

Regards
Vinay TJ