[SOLVED] Read From LOGFILE

[Mir]

Hi All

I have code which is working .But my problem is i want to Show from file one string only one time.

Example of logfile:-

123 kjhkjhlk
123 jhijio
234 fdfgd
989 nbnbnb
676 njnkj


Now i want ot show like this:-
123
234
989
676

So plz help me...

[sukatoa]

Here are some examples,

void ReadFile(File f) throws Exception {
      Scanner scan=new Scanner(f);
      while(scan.hasNext()){
            System.out.println(scan.next());
            scan.next();
      }scan.close();
}

or

void ReadFile(File f) throws Exception {
      Scanner scan=new Scanner(f);
      while(scan.hasNextLine()){
            System.out.println(scan.nextLine().split(" ")[0]);        
      }scan.close();
}

I haven't test it yet, try it....

[Mir]

i use both code in my programm.But out put is,It is printing may time.As i say i want to print only one time..

Plz help me

[Mir]

Plz help me any one

[Eranga]

Can you get all numbers, with duplicates.

[Mir]

Can you get all numbers, with duplicates.

which type of number...my log file number like is

123
122
1233
145
165
789
122
122
123
122

[Eranga]

Ok, now what you can do is, store them in a list and add one by one. Before adding the element check it's exist or not.

[Mir]

can you give me code of store in list and add one by one

[Eranga]

Got you what I say there?

[Eranga]

Ok, here is a way to do it.

import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;

/**
 *
 * @author Eranga Tennakoon
 */
public class FileRead {
    
    private ArrayList<String> str;
    
    public FileRead() {
        this.str = new ArrayList<String>();
    }
    
    private void getFileInfor(File myFile) {
        try {
            Scanner fileScanner = new Scanner(myFile);
            while(fileScanner.hasNextLine()) {
                doProcessing(fileScanner.nextLine());
            }
        } 
        catch (FileNotFoundException ex) {
            System.out.println(ex.getMessage());
        }
        printResult();
    }
    
    private void doProcessing(String strr) {
        String newStr = strr.split(" ")[0];
        removeDuplicates(newStr);
    }
    
    private void removeDuplicates(String s) {
        
        if(str.isEmpty()) {
            str.add(s);
        }
        else {
            for(int i = 0; i < str.size(); i++) {
                if(!str.contains(s)) {
                    str.add(s);
                }
            }
        }
    }
    
    private void printResult() {
        for(int i = 0; i < str.size(); i++) {
            System.out.println(str.get(i));
        }
    }
    
    public static void main(String[] args) {
        File dd = new File("files/mir_001.txt");
        new FileRead().getFileInfor(dd);
    }
    
}

[Mir]

yaa i got it.it's good if it working..

[Eranga]

Try an let me know is it work. ;)

[Mir]

it is not working accourding to you and me.It is simply print all string which is present in log file..

[Mir]

Thxs for code but it's out put like this

192.158.5.9	
192.158.5.9	
192.158.5.9
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9

And i want to show only one time

192.158.5.9

i mean all duplicate 192.158.5.9 don't want to show.

plz help me

[Eranga]

No you are wrong, it's perfectly work for me. I don't know what happened in your end.

[Eranga]

removeDuplicates() done it

[Mir]

plz see me log formate then try to run

[Eranga]

Are you talking about this.

192.158.5.9	
192.158.5.9	
192.158.5.9
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9	
192.158.5.9

[Mir]

yes

192.158.5.9	kjnkjnkn
192.158.5.9	kasasdas
192.158.5.9          asdsad
192.158.5.9	sadasdsad
192.158.5.9	sadsad
192.158.5.9	rtertre
192.158.5.9	rtret
192.158.5.9	cbvv
192.158.5.9	cvbnghh
192.158.5.9	fghfgn
192.158.5.9          tyty

[Eranga]

Yep, you get all of them as output. Reason is this.

The way of formated you log file and the way it handle on the code is not compatible. On a single line, number split depend on a single character space.

String newStr = strr.split(" ")[0];

But in your log file there is no space. I can see tab, in some lines more than one tab. So what happened is all are counted as not duplicated on each.

So, you get the output as

192.158.5.9	kjnkjnkn
192.158.5.9	kasasdas
192.158.5.9          asdsad
192.158.5.9	sadasdsad
192.158.5.9	sadsad
192.158.5.9	rtertre
192.158.5.9	rtret
192.158.5.9	cbvv
192.158.5.9	cvbnghh
192.158.5.9	fghfgn
192.158.5.9          tyty

Because no one is similar to each other.