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 05052008, 04:54 AM #1Member
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 05052008, 05:03 AM #2
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Did you Goole it. There should be some mathematical way to find it.
 05052008, 05:08 AM #3Member
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yes i did and cudnt find anything
 05052008, 05:23 AM #4
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Ok, here is a way.
Java Code:N = d + 2m + [3(m+1)/5] + y + [y/4]  [y/100] + [y/400] + 2
m  moth id(from 1 to 12 respectively)
y  year
Do the calculations and find the N. Keep in mind that to drop the remainder in each [] and only get the whole number. Don't rounding off numbers. Then divide the N by 7. Remainder give the answer, day of the week.
0  Saturday
1  Sunday
2  Monday
3  Tuesday and so on.
Try it and see.
 05052008, 05:41 AM #5
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Ah, made a mistake in my explanation. Here is an example for today(5/5/2008)
Java Code:N = 5 + 2(5) + [3(6)/5] + 2008 + [2008/4]  [2008/100] + [2008/400] + 2 N = 5 + 10 + 3 + 2008 + 502  20 + 5 + 2 N = 2515
d is not the number of days of the month. Days spending up to date which we want to processing.
Did you get it?
 05052008, 06:11 AM #6Member
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im trying to write in servlet and get in jsp
Last edited by veena; 05052008 at 02:40 PM.
 05052008, 06:13 AM #7
The way Eranga explain it is correct. except you have to account for leap years. which you do with an array I forget the exact table.
My IP address is 127.0.0.1
 05052008, 06:19 AM #8
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 05052008, 06:24 AM #9Member
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hey Eranga
when u add up N=2501
 05052008, 06:33 AM #10
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Is it.
Java Code:N = 1 + 2(1) + [3(2)/5] + 2008 + [2008/4]  [2008/100] + [2008/400] + 2 N = 1 + 2 + 1 + 2008 + 502  20 + 5 + 2 N = 5 + 2008 + 502  20 + 7 N = 2510  20 + 12 N = 2502
 05052008, 06:42 AM #11Member
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let me try again
Last edited by veena; 05052008 at 02:41 PM.
 05052008, 06:59 AM #12
 05052008, 07:00 AM #13
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Go it. I've miss a very important rule there. Really sorry about. Still I remembering this and let you know, because I do those things few years back when I'm in the university for maths.
You have to use numbers 13 and 14 for the months of January and February, with the previous year. In our discussion,
1/1/2008 should be 1/13/2007.
Lets try it.
Java Code:N = 1 + 2(13) + [3(14)/5] + 2007 + [2007/4]  [2007/100] + [2007/400] + 2 N = 1 + 26 + 8 + 2007 + 501  20 + 5 + 2 N = 2530
Lets do another example, for 20/2/2008. So the date should be 20/14/2007
Java Code:N = 20 + 2(14) + [3(15)/5] + 2007 + [2007/4]  [2007/100] + [2007/400] + 2 N = 20 + 28 + 9 + 2007 + 501  20 + 5 + 2 N = 2552
Keep in mind that, rule only valid for January and February.
 05052008, 07:15 AM #14Member
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yep i got it and did in servlet
when i was searching i got the same formula
any ways thnks very much
its a nice formula thoughLast edited by veena; 05052008 at 02:41 PM.
 05052008, 07:15 AM #15
I think you can just use the Gregorian calendar I think also.
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 05052008, 08:48 AM #16
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No matter what calender you used, my formula is working. We have used in few projects that formula, when I'm in the University.
 05062008, 05:03 AM #17
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Hey veena, no need to edit your post time to time. If you expecting the answer in different approaches please let it to others. Because later someone read your thread, really confused. :)
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