Hello,

I have a class to read the data from Excel
Java Code:
public class DistGridOp2DB{
public static void main(String[] args) throws Exception{

public static Set<DistributionGridOperator> readExcelFile(){
	try {
	    FileInputStream file = new FileInputStream(new File("c:\\50Hertz_Anlagenstammdaten.xls"));
Now you cann see that every time i need to go to the code and type the pathe and the name of the file, what to want to do, is how to be able to upload the file through web page, very simple web page let me browse and choose the file and then send the path of this file to class "DistGridOp2DB", how should
XML Code:
<html>
<body>
	<h1>File Upload</h1>
 
	<form action="" method="post" enctype="multipart/form-data">
 
	   <p>
		Select a file : <input type="file" name="file" size="45" />
	   </p>
 
	   <input type="submit" value="Upload It" />
	</form>
 
</body>
</html>
So what should i change in this form specifically with "action" and what should change in class DistGridOp2DB?