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 08042013, 05:13 PM #1Member
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Removing negative value after truncating
The question is to print value for sin and cos for degree 0 to 360 increment by 10.
Below is the code i wrote but the problem is after the value sin 360 becomes 0.0000 instead of 0.0000 after limiting to 4 decimal places(which is required by the question). How to solve this issue?
Issit should be done by hardcoding if (value < 0.00000001, Math.abs(value)?
or should I used value * 10000 / 10000 to limit to 4 decimal places and use decimal format to display the trailing zero?
Java Code:public static void main(String[] args) { for(int degree = 0; degree <= 360; degree += 10){ System.out.print(degree + "\t\t"); System.out.printf("%.4f", Math.sin(degree * Math.PI / 180)); } }
Last edited by dojob; 08042013 at 05:15 PM.
 08042013, 05:22 PM #2
 08042013, 05:33 PM #3
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Re: Removing negative value after truncating
You and I know that sin(x) == sin(k*360+x) but the poor computer doesn't know that; why not help it a bit?
Java Code:public static void main(String[] args) { for(int degree = 0; degree <= 360; degree += 10){ System.out.print(degree + "\t\t"); int d= degree%360; System.out.printf("%.4f", Math.sin(d * Math.PI / 180)); } }
JosThe only person who got everything done by Friday was Robinson Crusoe.
 08042013, 05:47 PM #4Member
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Re: Removing negative value after truncating
It will convert the insignificant negative value to absolute value 0.000000001 and after that 0.000 will be display? But it doesn't look proper to code it this way.
I have tried using decimal formatter and it seems the negative value still around for insignificant negative value.
 08042013, 05:49 PM #5Member
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 08042013, 05:50 PM #6
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Re: Removing negative value after truncating
Last edited by JosAH; 08042013 at 05:51 PM. Reason: wrong IEEE number ..
The only person who got everything done by Friday was Robinson Crusoe.
 08042013, 05:57 PM #7
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