[SOLVED] Simple Q: Values between Classes

[a45b22chp]

I searched through the posts for a bit but couldn't find the answer so...


I have 2 classes within one package. I want to access a value from class A in class B. I only need to do it once, and class A never even needs to act on the value once it is instantiated except to pass it to B.

class TCPServer {
public static void main(String argv[]) throws Exception
{
[COLOR="Red"]double X = 15[/COLOR];
}

class TCPClient {
public static void main(String argv[]) throws Exception
{

double Y = [B][COLOR="Red"]X[/COLOR][/B];
}

thanks in advance!

[sukatoa]

it is the same on how you access methods in other classes in the same package....

double b = new OtherClass().doubleVar;

[danielstoner]

If you declare the variables in a method (you declared them in main) then they are local to that method and cannot be seen anywhere else in the code (with some exceptions - see Local Inner Classes | Little Tutorials)

Your code should look like this:

class A
{
    public static double sX;
    public double X;
}

class B
{
    public static void main(String[] args)
    {
        double Y = new A().X;
        // or
        double Z = A.sX;
    }
}

[a45b22chp]

Each class is in it's own file.

Eclipse says:
"_____ cannot be resolved or is not a field"

any thoughts?

[DonCash]

Make 2 class files,

1 called A and one called B.

class A:

public class A {
	
	public static double Ax()
	{
		double X = 15;
		return X;
	}

}

class B:

public class B {

	public static void main(String[] args) {
		
		A a = new A();
		double Y = a.Ax();
		System.out.println(Y);
	}

}

Output:

15.0

I've just ran this in Eclipse and it works fine.

[a45b22chp]

thanks DonCash, for the help and the quick response


just curious, how would class B call 2 different values from A? would class A need to define more than one method, and each method can return one value?

[DonCash]

No problem. Yeah just add some more methods to class A and call them the same way in B.

You only need to create the A object once.

A a = new A();