Can't solve error message while looping

[BHCluster]

Finally after few posts and few attempts I have managed to read text file and out put it on the screen. The file has 60 lines of data in three columns. Every thing works until I try to read 1 row of three doubles for calculation. So when I had this:

Code:

double[] gene={-9.30, 5.65, -5.02};
double[] gene1={-5.30, 3.65, -2.02};

it worked perfect but when I have tryed to read gen1 from the file with the use of errors I get this error:

Code:

G:\Read File\csv.java:145: parseDouble(java.lang.String) in java.lang.Double cannot be applied to (java.lang.String[])
	double ii = Double.parseDouble(myarray);
	                  ^
1 error

Tool completed with exit code 1

If anybody know what the problem is please help me cos I am running out of ideas. Here is the full program:

Code:

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileInputStream;
import java.io.FileWriter;
import java.io.InputStreamReader;
import java.io.Writer;
import static java.lang.Math.*;

public class csv {

public static void Manhattan(double[][] a,double[][] b,int n,int n2)
  {
    int q=n2;
    int c=n;
    for(int m=0;m<q;m++)
    {
      for(int h=0;h<q;h++)
      {
        double d=0;
        double d2=0;
        for(int j=0;j<c;j++)
        {
          d2=a[m][j]-a[h][j];
          if(d2<0)
          d2=d2*-1;
          d=d+d2;
          }
        b[m][h]=d;

      }
    }

  }


public static double Euclidean(double[] array1, double[] array2)
{
	//Store the numbers of the both arrays
	double x1= array1[0];
	double y1=array2[0];
	double x2= array1[1];
    double y2= array2[1];
    double x3=array1[2];
    double y3=array2[2];

	//Compute the minus part of the formula
	double minusResult1 = y1-x1;
	double minusResult2 = y2-x2;
	double minusResult3 = y3-x3;

	//Square the answers
	double square1 = pow(minusResult1, 2);
 	double square2 = pow(minusResult2, 2);
    double square3 = pow(minusResult3, 2);

	//Sum the squares
	double sumOfSquares = square1+square2+square3;

	//Get the square root of the sumOfSquares
	double finalResult = sqrt(sumOfSquares);

	return finalResult;
}

public static double Manhattan(double[] array1, double[] array2)
		{

//Store the numbers of the both arrays
double x1= array1[0];
	double y1=array2[0];
	double x2= array1[1];
    double y2= array2[1];
    double x3=array1[2];
    double y3=array2[2];

	//Compute the minus part of the formula
	double minusResult1 = y1-x1;
	double minusResult2 = y2-x2;
	double minusResult3 = y3-x3;
     //Square the answers
	double abs1 = abs(minusResult1 );
 	double abs2 = abs(minusResult2);
    double abs3 = abs(minusResult3 );

	//Sum the squares
	double sumOfAbs = abs1+abs2+abs3;

	//Get the square root of the sumOfAbs
	double finalResult = sqrt(sumOfAbs);

	return finalResult;
}

public static double Pearson(double[] array1, double[] array2)
{
	//Store the numbers of the both arrays
	double x1= array1[0];
	double y1=array2[0];
	double x2= array1[1];
	double y2= array2[1];
    double x3=array1[2];
    double y3=array2[2];

	//Compute the minus part of the formula
	double mean1 = (x1 + x2 + x3)/3;
	double mean2 = (y1 + y2 + y3)/3;

	double t = (x1 - mean1)*(y1 - mean2) + (x2 - mean1)*(y2 - mean2) + (x3 - mean1)*(y3 - mean2);


	//Square the answers
	double square1 = sqrt((x1 - mean1)*(x1 - mean1) + (x2 - mean1)*(x2 - mean1) + (x3 - mean1)*(x3 - mean1));
	double square2 = sqrt((y1 - mean2)*(y1 - mean2) + (y2 - mean2)*(y2 - mean2) + (y3 - mean2)*(y3 - mean2));


	//Get the square root of the sumOfSquares
	double finalResult = t/(square1*square2);

	return finalResult;
}



public static void main(String[] args) throws Exception {


	// Set file name & path
	String filepath = "Data_Set_1.txt";
	//String output = "Output_Data_Set_1.txt";

	// Read in file
	FileInputStream in = new FileInputStream(filepath);
	BufferedReader br = new BufferedReader(new InputStreamReader(in));
	String strLine;

	//Write file
	//FileOutputStream out = new FileOutputStream(output);
	//BufferedWriter wr = new BufferedWriter(new OutputStreamWriter(out));

	// Declare Array which will hold 61 lines
	String[] myarray;
	myarray = new String[61];


	double ii = Double.parseDouble(myarray);



	// Read each line into the array
	for (int i = 0; i < myarray.length; i++){
		myarray[i] = br.readLine();
	}

	in.close();



	// Print out array info in desired order. Delete " characters
	for (int i = 1; i < myarray.length; i++){
		System.out.println(myarray[i].replace("\"", ""));

	}

		double[] gene={-9.30, 5.65, -5.02};
		double[] gene1={ii};

	for (int i = 1; i < myarray.length; i++){
		double EuclideanDist = Euclidean(gene, gene1);
		System.out.println("Euclidean distance = " + EuclideanDist);

		double ManhattanDist = Manhattan(gene, gene1);
		System.out.println("Manhattan = " + ManhattanDist);

		double PearsonDist = Pearson(gene, gene1);
		System.out.println("Pearson = " + PearsonDist);
	}

  }
}

Text file looks like this:

Code:

-9.30 5.65 -5.02
-4.10 5.68 0.56
4.75 0.11 2.86
-1.54 -10.01 -1.99
-6.29 5.62 -2.78
-13.02 1.31 1.61
-5.85 3.79 -6.56
-12.71 -0.45 0.62
-3.05 -12.65 -5.07
2.18 -5.82 -9.73
1.74 -0.99 -3.66
-7.88 0.93 -8.33
-6.34 -1.85 -4.00

Thank you!

[Java Tip]

It looks like you are tying to convert a String array to double. This is the wrong approach. You should convert each array element to double value and if necessary store it in a double array afterwards. Write a loop and convert each string value one by one in this loop.

[BHCluster]

Thanks for taking interest but can you show me how to do that cos I have lost my brain trying to crack it.

[sukatoa]

Yes, You can do that....
Try to convert the String elements in that String array to Double....

Not Array of String to Double.... Do you know about Java Core API docs?

regards,
sukatoa

[BHCluster]

Dude if new that I would not be bothering you. Please show me how to do this. Please.

[sukatoa]

Code:

String data[] = {"1.1","2.2","3.3","4.4"};
Double converted[] = new Double[5];
int x=0;
while(x<5){
      converted[x] = Double.parseDouble(data[x]);x++;     
}

Try to have an experiment on it....

regards,
sukatoa

[Eranga]

Quote:

Originally Posted by sukatoa

Code:

String data[] = {"1.1","2.2","3.3","4.4"};
Double converted[] = new Double[5];
int x=0;
while(x<5){
      converted[x] = Double.parseDouble(data[x]);x++;     
}

Try to have an experiment on it....

regards,
sukatoa

Nice work pal, and good practice

Code:

String[] data = {"1.1","2.2","3.3","4.4"};

[DonCash]

Quote:

Dude if new that I would not be bothering you. Please show me how to do this. Please.

To be serious in Java you really need to start looking at the API.

Java 2 Platform SE 5.0

[CaptainMorgan]

Quote:

Originally Posted by DonCash

To be serious in Java you really need to start looking at the API.

Right on!

BH- check out the Java 6 API too.

[Eranga]

Captain, Don, sukatoa,

Does anyone of you know an application where we can find all Java doc, APIs and so on. A link...!

[CaptainMorgan]

Quote:

Originally Posted by Eranga

Captain, Don, sukatoa,

Does anyone of you know an application where we can find all Java doc, APIs and so on. A link...!

Eranga, I'm afraid I don't understand what you mean by application that finds the API's.... if you're looking for the many different APIs- they're all located on Sun's site...

[Eranga]

Ah, application mean a program like MSDN. I seen such a tool one of my friend use. But he don't give any detail about it.

What I try to do is make a collection of APIs and Docs myself.

[DonCash]

Are you looking to write your own APIs & Docs? Have you read about the JavaDoc tool?

javadoc-The Java API Documentation Generator

[Eranga]

No Don, I'm not try to write my own stuff. I just want to make a collection. Say I'm working without a network connection, if I have a such collection no need to worried about

[DonCash]

Oh right... You want to download the entire API documents to your computer.

I think they are available for download but i'm not sure where they are. I cant seem to find them.

You could try software that downloads the entire contents of a webpage. Check google..

[Eranga]

Yes few softwares available which can we used. But the reason is, not possible to find all of them in a single place.