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  1. #1
    Zebra's Avatar
    Zebra is offline Member
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    Default Quotients/Remainders (Loops *Need Help*)

    Write a program that finds the quotients and remainders of all the numbers
    between 200 and 225 when they are divided by x, where x= 11 if the number
    is even and x is 14 if the number is odd. Here's what the output should
    look like.

    OUTPUT:
    Attached Thumbnails Attached Thumbnails Quotients/Remainders (Loops *Need Help*)-output-copy.jpg  
    I am a Java n00b.

  2. #2
    sukatoa's Avatar
    sukatoa is offline Senior Member
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    Default

    You know what?!! if you don't try to do it yourself first, you will never realize how lovable java programming is....

    An ideal forum was designed to help/discuss other members about there problem or new ideas, sharing it with them while learning....

    And not to feed them ( Posting the complete code )....

    don't be on a hurry,
    sukatoa

  3. #3
    sanjeevtarar's Avatar
    sanjeevtarar is offline Senior Member
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    Default

    Hello Zebra,

    I think your problem is not much hard...just think about the logic and do some paper work, it will help you lot.

    First try it at your self...OK

    however i have done this.

    Java Code:
    public class FindQuotientsRemainders 
    {
    	public static void main(String[] args){
    		getNumber();
    	}
    
    	public static void getNumber(){
    		int evenX = 11;
    		int oddX = 14;
    
    		for (int i=200;i<=225;i++ ){
    			int quoti = 0,rema = 0;
    			if(i%2==0){
    				quoti = i/evenX;
    				rema = i%evenX;
    				System.out.println("When "+i+" is divided by "+evenX+", the quotients is "+quoti+" and remainders is "+rema);
    			}else{
    				quoti = i/oddX;
    				rema = i%oddX;
    				System.out.println("When "+i+" is divided by "+oddX+", the quotients is "+quoti+" and remainders is "+rema);
    			}
    		}
    	}
    }

    sanjeev

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