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Thread: Poker Hand Evaluator Help
 04122013, 06:27 AM #1Senior Member
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Poker Hand Evaluator Help
How do I make boolean methods to check for if 5 cards have: pair, two pair, 3 of a kind, straight, flush, full house, 4 of kind,
straight flush.
This is what I have for flush and it worked. I need help on the others.
ex:
Java Code:int suit = cards[0].getSuit(); //Find 1 suit of 1 card for (int i = 1; i <= 4; i++){ if (suit != (cards[i].getSuit())){ //If suit of first card does not equal suit of other cards, there is no flush return false; } } return true; }
 04122013, 06:38 AM #2Member
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Re: Poker Hand Evaluator Help
Pair: Check each card against every other card. If any two are same, it's a pair.
Two Pair: Same as pair but once you find one pair, take out those cards and recheck.
Three of a Kind: Same as pair except check against two other cards instead of one.
Straight: Find lowest card and search remaining cards for next number and next etc. Ex: 3 is lowest. Search for 4. If found, search for 5...
Flush: Done.
Full House: Check for three of a kind, then check if remaining two cards equal each other.
Four of a Kind: Same as three of a kind except check against three other cards instead of two.
Straight Flush: If it is a straight, and it is a flush, it is also a straight flush.
Good luck.Last edited by Prime624; 04122013 at 06:45 AM.
 04122013, 07:07 AM #3Senior Member
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Re: Poker Hand Evaluator Help
here's what i got for 4 of a kind. What do you think?
Java Code:public static boolean hasFourOfAKind(Card[] cards){ int count = 0; for (int i = 0; i <= 4 ;i++){ count = 0; for (int j = i+1 ; j <= 4 ; j++){ if (cards[i] == (cards[j])){ count++; } if (count == 4){ return true; } } } return false; }
 04122013, 08:52 AM #4Senior Member
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Popopopoker face... Poker Hand Evaluator Help
Hi. How do I make boolean methods to check for if 5 cards have: pair, two pair, 3 of a kind, straight, flush, full house?
This is what I have so Far:
PAIR
Java Code:public static boolean hasPair(Card[] cards){ int count = 0; for (int i = 0; i <= 4 ;i++){ count = 0; for (int j = i + 1 ; j <= 4 ; j++){ if (cards[i] == (cards[j])){ count++; } if (count >= 1){ return true; } } } return false; }
TWO PAIR
no idea how to find another pair not equals the first pair foound
THREE OF A KIND
Java Code:public static boolean hasThreeOfAKind(Card[] cards){ int count = 0; for (int i = 0; i <= 4 ;i++){ count = 0; for (int j = i + 1 ; j <= 4 ; j++){ if (cards[i] == (cards[j])){ count++; } if (count >= 2){ return true; } } } return false; }
STRAIGHT
no Idea how to begin sorting
FLUSH
Java Code:public static boolean hasFlush(Card[] cards) int suit = cards[0].getSuit(); //Find 1 suit of 1 card for (int i = 1; i <= 4; i++){ if (suit != (cards[i].getSuit())){ //If suit of first card does not equal suit of other cards, there is no flush return false; } } return true; }
FULLHOUSE
no idea how to call my methods
 04122013, 08:59 AM #5
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Re: Popopopoker face... Poker Hand Evaluator Help
Inroduce a temporary array 'count' that (after your loop(s) have finished) contains the number of cards of a certain rank; e.g. coun[7]= 2 means that the hand contains two sevens. If the array contains two number 2s, you have two pairs, if the array contains a 2 and a 3, you have a full house. etc.
kind regards,
JosThe only person who got everything done by Friday was Robinson Crusoe.
 04122013, 09:28 AM #6
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Re: Poker Hand Evaluator Help
@OP: I've merged your two threads; please don'y start multiple threads for the same subject.
kind regards,
JosThe only person who got everything done by Friday was Robinson Crusoe.
 10032013, 06:07 AM #7
Re: Poker Hand Evaluator Help
You can expand your hasFourOfAKind method to handle all combinations. By that I mean the value stored in count will be unique for pair (1), two pair (2), three of a kind (3) etc. Just use one method to do all the counting then use a switch on the result to determine the hand. No need to have multiple methods duplicating the work. Straights and flushes need to handled separately.
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