Re: Java Phonebook With Arrays // HELP! //

[Zoul787]

I have the same excercise but different problem hope you guys can help.
Here's my code:

import java.util.*;
public class PhoneBook {

public static void main(String[] args) {
//Initializing scanner array 'friends' ,'phone' and variable.
Scanner sc = new Scanner(System.in);
String[] friends = new String[20];
String[] phone = new String[20];
String name;
String entry = "zzz";
int count = 0;

//Prompting user to input Array elements.
do{
System.out.println("Enter a friends name:");
name = sc.nextLine();

if(name.equalsIgnoreCase(entry)){
System.out.println("Thank you.");
}
else{
friends[count] = name;
System.out.println("Enter your friends phone number (XXX-XXX-XXXX)");
phone[count] = sc.nextLine();
}
count++;

}while(name.equalsIgnoreCase("zzz") || count <= 19);

}
}


I'm stuck at the while command which wont recognize the "zzz"

[Norm]

Post moved to its own thread.

while command which wont recognize the "zzz"

Add a println() to print out the value of name and count just before the while statement so you can see what the computer sees when the code executes.

You do release what an OR operator will do? If either of the expressions is true, the while will loop.
I'd guess that it will loop about 19 times

[Zoul787]

I have the same exercise but different problem. I'm stuck in a while loop which wont recognize when "Zzz" is entered and the program thinks its a name can someone help me out?
Here's the code:

import java.util.*;
public class PhoneBook {

    public static void main(String[] args) {
    	//Initializing scanner array 'friends' ,'phone' and variable.
    	Scanner sc = new Scanner(System.in);
    	String[] friends = new String[20];
    	String[] phone = new String[20];
    	String name;
    	String entry = "zzz";
    	int count = 0;

    	//Prompting user to input Array elements.
    	do{
    		System.out.println("Enter a friends name:");
    		name = sc.nextLine();

    		if(name.equalsIgnoreCase(entry)){
    			System.out.println("Thank you.");
    		}
    		else{
    			friends[count] = name;
    			System.out.println("Enter your friends phone number (XXX-XXX-XXXX)");
    			phone[count] = sc.nextLine();
    		
    		}
    		count++;

    	}while(name.equalsIgnoreCase(entry) || count <= 19);
    	System.out.println("The number of friends you entered is: "+count);
    	System.out.println("");

    }
}

[SJF]

while(name.equalsIgnoreCase(entry) || count <= 19)

WHILE count < 20 OR name = zzz THEN count += 1 and Keep Going

isn't really what you meant? I'm guessing WHILE count < 20 and name NOT zzz ?

[Zoul787]

Finished it thank you for responding though, ended up with for loops but I imagine if I did this it work also

while loop section of previous code:

 do{
            System.out.println("Enter a friends name:");
            name = sc.nextLine();
 
            if(name.equalsIgnoreCase("Zzz"))break;

            else{
                friends[count] = name;
                System.out.println("Enter your friends phone number (XXX-XXX-XXXX)");
                phone[count] = sc.nextLine();
             
            }
            count++;
 
        }while(count <= 19);

Completed Code

import java.util.*;
public class PhoneBook {

    public static void main(String[] args) {
    	//Initializing scanner array 'friends' ,'phone' and variable.
    	Scanner sc = new Scanner(System.in);
    	String[] friends = new String[20];
    	String[] phone = new String[20];
    	String name;
    	String nameAns;
    	int count = 0;

    	//Prompting user to input Array elements.
    	for (int i = 0; i <= 19; i++) {
    		System.out.println("Enter a friends name:");
    		name = sc.nextLine();
    		
    		//If user enters "Zzz" automatically breaks for loop
    		if(name.equalsIgnoreCase("zzz"))break;
    		else{
    			friends[i] = name;
    			System.out.println("Enter your friends phone number (XXX-XXX-XXXX)");
    			phone[i] = sc.nextLine();
    			count ++;
    		}
    	}
    	//Displays amount of friends typed in
    	System.out.println("\nThe number of friends you entered is: "+count);
    	//Displays the names typed in
    	System.out.println("The names you entered are:");
    	for (int i = 0; i <= 19; i++) {
    		//When an element of the array equals null automatically breaks the for loop
    		if(friends[i]== null)break;
    		
    		else {
    			//Prints the names
    			System.out.println(friends[i]);	
    		}			
    	}
    	System.out.println("Enter one of the names:");
    	nameAns = sc.nextLine();
    	//Quick scan of all the elements
    	for (int i = 0; i <= 19; i++){
    		//If the variable nameAns equals one of the elements in the array quickly prints 
    		//it out and the number corresponding to it.
    		if (nameAns.equalsIgnoreCase(friends[i])){
    			System.out.println(friends[i]+": "+phone[i]);
    		}
    	}
    }
}

[LaughingSeraph]

I am a little curious as to why you are using i<= 19 instead of < array.length and so on?

[Zoul787]

I'm still new to this :)