Java Exception Handling regarding Constructor

[DeepakDev]

Hi Everybody

In the below code ...If i remove constructor Test11(int i) or change it to Test11(int i) throws Exception then it compile and run.Can anybody clarify why compiler ask to include throws clause in constructor Test11(int i)...though I am explicitly calling Test11() by .... Test11 t = new Test11();


public class Test11 extends A
{
Test11()throws Exception{
System.out.println("Test10 Class");
}
Test11(int i)
{
System.out.println("Test10 Classdfdfdfdff");
}
public static void main(String args[]) throws Exception{

Test11 t = new Test11();
}
}
class A
{
A() throws Exception{
System.out.println("A Class");
}
}


Why does it do so when it does not explicitly or implicity get the Exception

Thanks
DeepakDev

[DarrylBurke]

Moved from a staff-only section.

db

[DarrylBurke]

Cross posted and didn't have the courtesy to reply to the second response there before asking the same question here:
Java Exception Handling regarding Constructor (Java in General forum at JavaRanch)

db

[PhHein]

Thanks for the heads up, Darryl.
ignoreList++