Object array toString();

[sethe23]

Hi, there is something missing here, but I am not sure what. I have 3 classes. 1 class has the method

public  Name(String x, String y, double z) {

The 2nd class has the code that accesses the "name" method

void addName(String a, String b, doublec)
    {
        data[count] = new nameofClass1(e, f, g);
        ++count;
    }

And the 3rd class is the where the main method is with a display of this.

I cannot for the life of me figure out how to to display all the values for data[i].

I need it to be a toString method. I have tested data[i].x; to make sure that the String passed is located there and it is.

I am just not able to toString() that whole index of the object array.

Thanks in advance

[sethe23]

In summary, why won't data[i].x.toString(); work?

[Ronin]

Hi sethe23,

Can you please explain exactly what you are trying to output from the toString() method. The complete code woud also help to troubleshoot.
Assuming data[i].x is a String then calling the toString() method explicitly is redundant.

If you are attempting to display some or all the attributes of the data[i] object you will need to override the toString() method.

Regards.

[sethe23]

2 strings and a double. Basically, its a string giving the name, date, and a double value.

[Ronin]

If its the three parameters you want to print out then you will need to ensure the variables within the object are being updated with the values passed in the Constructor's signature. You will then need to override the toString() method of the Name class.

From here you will need to call the toString() method from data[i] instead of data[i].x as you have been.

Regards.

[sethe23]

So data[i].toString (); I believe I tried and got an error.

[Tolls]

Post the complete exception, including stack trace, and the relevant area of code it is thrown from.

[Ronin]

Did you override the method?

[sethe23]

Well its not a runtime error, but it displays name@ and a hex reference

[Tolls]

Then you haven't written a toString() method.
That's not an error, that's the default toString() at work.
<Classname>@<address>

[sethe23]

Ouch, so what am I missing from this?

[Tolls]

Apart from a toString() method on whatever class you have in your array?

Can't tell, as you've not posted much relevant code as far as I can see.

[sethe23]

Ok, I will post it entirely when I get home.