int/double

[Droid_X]

What is the difference? If I use this to calculate the square root of a number using Math.pow(), I get a decimal. I am guessing it has to do with int/double.

class hi{
	public static double squareRoot(int a){
		return Math.pow(a, 0.5);
	}
	public static void main(String args[]){
		System.out.println(squareRoot(16));
	}
}

[Wnt2bsleepin]

Data Types

Basically, a double is a floating point number i.e: 2.3
An int is a whole number integer i.e: 5

[Droid_X]

Ah ok.

So how would I make it return an int?

If I replace this:

public static double squareRoot(int a)

with:

public static int squareRoot(int a)

I get an error.

[Wnt2bsleepin]

Math.pow

See if you can figure out why it won't let you return an int.

[Droid_X]

Oh, Math.pow only takes a double. I just converted the double to an int.

class apples{
	public static double squareRoot(double a){
		return Math.pow(a, 0.5);
	}
	public static void main(String args[]){
		int num = (int)squareRoot(16);
		System.out.println(num);
	}
}

[Wnt2bsleepin]

Just a small correction, it returns a double. You can convert an int to a double easily, the reverse is not as easy. That is why it lets you give it an int as an option because it converts it to an integer.

		double a = 5.4;
		int b = (int)a; 
		
		int c = 6;
		double d = c;