have problem with my program !

[freedom12]

Hello, I have a problem that I don't know how to get the sum of separate numbers .


the program I built

the question is

Write a Java application that reads from the user a positive integer less than 2147483648.
Then separates the integer into its individual digits and prints a message indicating if the
sum of its digits is odd or even.
Example:
If the user enters 35271, the message should be: The sum of the digits of 35271 is even.
Explanation:
3 + 5 + 2 + 7 + 1 = 18 which is even.

 public static void main(String[] args){

   Scanner in= new Scanner (System.in);


     int number,sum;
      
     number=in.nextInt();
     
   
     while (number >0){
         
       sum= number %10;  
          number= number /=10;
            
       System.out.print( sum);
       
       
     // if (number %2 == 0)   {

// System.out.println("The sum of the digits of is even"); 
 
 }
      
 //else {
 //System.out.println("The sum of the digits is odd"); 
     
   
 }
         
      
         
}

As you see I'm always the same input number .



So please help me to solve this problem .

[JosAH]

Where are you adding the digits of the number?

kind regards,

Jos

[freedom12]

Where are you adding the digits of the number?

kind regards,

Jos

I didn't copy the whole program so , I forgot to but "import java.util.Scanner;"

import java.util.Scanner;
public class Q4_601110813 {
    

 public static void main(String[] args){

   Scanner in= new Scanner (System.in);


     int number,sum;
      
     number=in.nextInt();
     
   
     while (number >0){
         
       sum= number %10;  
          number= number /=10;
            
       System.out.print( sum);
       
       
     // if (number %2 == 0)   {

// System.out.println("The sum of the digits of is even"); 
 
 }
      
 //else {
 //System.out.println("The sum of the digits is odd"); 
     
   
 }
         
      
         
}

[DarrylBurke]

Please go through the Forum Rules, particularly the third paragraph.

db

[freedom12]

Please go through the Forum Rules, particularly the third paragraph.

db

I'm sorry , can you fix it to " how to get the sum of separate numbers (problem)"

[freedom12]

please it's a simple problem + I want the solution as soon as possible .

[JosAH]

please it's a simple problem + I want the solution as soon as possible .

Don't try to hurry us, it is of no use at all; and my question still stands (see reply #2)

kind regards,

Jos

[freedom12]

Don't try to hurry us, it is of no use at all; and my question still stands (see reply #2)

kind regards,

Jos

NP ^^ , Ok

I add input in

 int number,sum;
       
     number=in.nextInt();

particularly in variable "number"

[JosAH]

That part of the code only obtains an int from the user ...

kind regards,

Jos

[freedom12]

That part of the code only obtains an int from the user ...

kind regards,

Jos

If so , what should I do . I tried to change int to long , put no change !.

second , as I know it's similar if you take number from the user or initialize it ,so what did you mean ?

---------

[monkeyjr97]

you are asking for one int, so user might input 70237 for example, which would set that as the number variable.

a quick way to do this, probly not the best but loop put it in a do while so it keeps asking the user for ints and create a running total for the ints so they keep on adding:

then have the while statement saying if user inputs 0 it quits the method. so something like

   public static void main(String[] args){
        Scanner in= new Scanner (System.in);

        int number,sum;
        int runningTot=0;
        do{
            System.out.println("enter number to add, type 0 to quit");
            number=in.nextInt();
            
            runningTot += number;
            System.out.println("current total is " + runningTot); //you will need to take this basic info and do what you wish to it
        }while(number !=0);
    }
}

BUT IF I WAS YOU ID CREATE SEPARATE METHODS FOR THIS, I WOULDN'T DO IT ALL FROM THE MAIN or call it from different classes, it makes it all easier to manage.

[freedom12]

you are asking for one int, so user might input 70237 for example, which would set that as the number variable.

a quick way to do this, probly not the best but loop put it in a do while so it keeps asking the user for ints and create a running total for the ints so they keep on adding:

then have the while statement saying if user inputs 0 it quits the method. so something like

   public static void main(String[] args){
        Scanner in= new Scanner (System.in);

        int number,sum;
        int runningTot=0;
        do{
            System.out.println("enter number to add, type 0 to quit");
            number=in.nextInt();
            
            runningTot += number;
            System.out.println("current total is " + runningTot); //you will need to take this basic info and do what you wish to it
        }while(number !=0);
    }
}

BUT IF I WAS YOU ID CREATE SEPARATE METHODS FOR THIS, I WOULDN'T DO IT ALL FROM THE MAIN or call it from different classes, it makes it all easier to manage.

Thank you , it was helpful, but it wasn't what I asked for!

I want a program that separate the number then add them , for example :

if the input were 566 it means 5+6+6= 17 , then to determine if it's odd number or even !

and I have the program , but I want to use while loop instead of all these digits

import java.util.scanner;
public class intnumbers {
public static void main (string [] args) {
    int sum=0;
    int digit1, digit2, digit3, digit4, digit5, digit6, digit7, digit8,
            digit9, digit10;
    scanner input = new scanner(system.in);
    system.out.print("enter the posistve integer leass than 2147483648 ");
    int no = input.nextint();
    while (no <=   2147483648 ) {
     digit1=no%10; no/=10;  
     digit2=no%10; no/=10;
     digit3=no%10; no/=10;
     digit4=no%10; no/=10; 
     digit5=no%10; no/=10;  
     digit6=no%10; no/=10;  
     digit7=no%10; no/=10;  
     digit8=no%10; no/=10;
     digit9=no%10; no/=10;  
     digit10=no%10; no/=10;  
     total=total+digit1 + digit2 + digit3 + digit4 + digit5 + digit6 + digit7 + digit8 +
            digit9 + digit10; }
     switch (sum%2) {
         case 0 : System.out.println("the sum no is even");
         case 1 : System.out.println("the sum no is odd");
             
     }
    }
    
}

[freedom12]

Thank you very much for trying to help me . I've done the program , and I'll ask you if I face any problem .

Best wishes.