Ambiguos JAVA

[ALINAMARIA]

How can you define the classes Adult, Student and Engineer so that the next sequence to give compilation error only where specified?

class Test {
public static void main(String args[]) {
Adult a = new Student(); //without giving compilation error
Adult b = new Engineer();//without giving compilation error
a.explorare(); //without giving compilation error
b.explorare(); //without giving compilation error
a.afisare(); //without giving compilation error
b.afisare(); //compilation error

[DarrylBurke]

Moved from Advanced Java. Homework questions belong here, not there.

db

[Tolls]

What have you tried?

[fillaru0]

I thing you want to use inheritance (between Adult, Student and Engineer) in such a way that you get a compilation error when you call “b.afisare()”.

If it is so then, I feel it won’t happen as variable “a” and “b” are of same type ‘Adult’. So when you call “a.afisare()” or “b.afisare()” compiler will check the method signature in Adult class only (never the subclass). So when “a.afisare()” compiles even “b.afisare()” will compile.

[Tolls]

Well spotted.
I missed that they were both declared as Adults.

[fillaru0]

Thanks Tolls.