ArrayIndexOutOfBounds Help

[whitedragon551]

I have to use a try block to loop through each item in the array and increase a subscript by 1. Then I have to use a catch block that catches the ArrayIndexOutOfBoundsException and displays a message.

I cant seem to get it to throw the message: Now Youve Gone Too Far. How do I go about creating this message as it tries to display a 6th number that is not in the array?

//GoTooFar.java by Tyler 11/11/2012

import java.util.*;

public class GoTooFar
{
	public static void main(String[] args) 
	{
	Date today = new Date();
	try
	{
		
		//Display intro window
		System.out.println("GoTooFar" + "\nby Tyler " + today);
		
		//Initialize arrays
		int[] numbers = {10 , 11 , 12 , 13 , 14};

		//Display each number in array
		for (int i = 0; i < numbers.length; ++i)
		{
			System.out.print(numbers[i] + "\n");
		}
	}
	catch(ArrayIndexOutOfBoundsException exception)
	{	
		System.out.println("Now Youve gone too far");
		System.exit(0);
	}
	}
}

[DarrylBurke]

Well, your loop doesn't try to go too far.

db

[whitedragon551]

Well, your loop doesn't try to go too far.

db

Ive tried this:

for (int i = 0; i < numbers; ++i)

And it will only display whats in the array. How do I make it try to display a 6th array element without adding a 6th array element?

[Jdsfighter]

        for (int i = 0; i <= numbers.length; ++i)
        {
            System.out.print(numbers[i] + "\n");
        }

[whitedragon551]

        for (int i = 0; i <= numbers.length; ++i)
        {
            System.out.print(numbers[i] + "\n");
        }

Thank you.