ArrayIndexOutOfBounds Help

I have to use a try block to loop through each item in the array and increase a subscript by 1. Then I have to use a catch block that catches the ArrayIndexOutOfBoundsException and displays a message.

I cant seem to get it to throw the message: Now Youve Gone Too Far. How do I go about creating this message as it tries to display a 6th number that is not in the array?

Code:

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//GoTooFar.java by Tyler 11/11/2012

import java.util.*;

public class GoTooFar
{
        public static void main(String[] args)
        {
        Date today = new Date();
        try
        {
               
                //Display intro window
                System.out.println("GoTooFar" + "\nby Tyler " + today);
               
                //Initialize arrays
                int[] numbers = {10 , 11 , 12 , 13 , 14};

                //Display each number in array
                for (int i = 0; i < numbers.length; ++i)
                {
                        System.out.print(numbers[i] + "\n");
                }
        }
        catch(ArrayIndexOutOfBoundsException exception)
        {       
                System.out.println("Now Youve gone too far");
                System.exit(0);
        }
        }
}

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Well, your loop doesn't try to go too far.

db

Quote:

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Originally Posted by DarrylBurke

Well, your loop doesn't try to go too far.

db

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Ive tried this:

Code:

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for (int i = 0; i < numbers; ++i)

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And it will only display whats in the array. How do I make it try to display a 6th array element without adding a 6th array element?

Code:

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        for (int i = 0; i <= numbers.length; ++i)
        {
            System.out.print(numbers[i] + "\n");
        }

---

Quote:

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Originally Posted by Jdsfighter

Code:

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        for (int i = 0; i <= numbers.length; ++i)
        {
            System.out.print(numbers[i] + "\n");
        }

---

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Thank you.