Coding error :L

So ive got a basic code that is throwing the following error :- java.lang.ArrayIndexOutOfBoundsEception

Apparently The getIndexs array is too small to support 19 indexes and im not sure how to fix it.

This is only a code snippet but you can see the return (lastArchiveId * 256 + Cache.STORE.getIndexes()[19] where the issue crops up

Code:

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//22314


        public static final int getItemDefinitionsSize() {
                int lastArchiveId = Cache.STORE.getIndexes()[19].getLastArchiveId();
                return (lastArchiveId * 256 + Cache.STORE.getIndexes()[19]
                                .getValidFilesCount(lastArchiveId)) - 22314;
        }
       
        public static boolean itemExists(int id) {
                if(id >= getItemDefinitionsSize()) //setted because of custom items
                        return false;
                return Cache.STORE.getIndexes()[19].fileExists(id >>> 8, 0xff & id);
        }

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Here is more on the specific error :-

[Launcher] Initing Cache...
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 19
* * * *at com.rs.utils.Utils.getItemDefinitionsSize(Utils.ja va:268)
* * * *at com.rs.cache.loaders.ItemsEquipIds.init(ItemsEquip Ids.java:13)
* * * *at com.rs.Launcher.main(Launcher.java:64)
Press any key to continue . . .

Quote:

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Originally Posted by mattd25

Here is more on the specific error :-

[Launcher]Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 19

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The index of an array is always zero based. So if you initialize an array of int with [10] the first element in the array will have the index 0 and the last element the index 9! Using an index greater than 9 will cause a java.lang.ArrayIndexOutOfBoundsException. So be careful with your indexes bounds!