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Old 03-10-2008, 02:56 AM
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kizilbas1 is on a distinguished road
HashMap String Return
Hi,

I'am having difficulty to make this work.

I have a class named Contest and List. Contest constructor has few parameters and also have another parameter which is called 'locations'. What i need to do is that in my List class, I have to use the return method i have created in Contest class and use that method to return all locations used for contests in the HashMap that I created in List class. It is just too difficulty, confusing I can't even demonstrate the idea clearly lol Help please :?

regards
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Old 03-10-2008, 04:34 AM
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hardwired is on a distinguished road
Code:
import java.util.*; public class ContestLocations { public static void main(String[] args) { ContestList contestList = new ContestList(); // Add some Contests. contestList.addContest(new Contest("sing", "12 Mar", "Dallas, TX")); contestList.addContest(new Contest("draw", "19 Mar", "Tampa, FL")); contestList.addContest(new Contest("ride", "22 Mar", "Stockton, CA")); contestList.addContest(new Contest("sail", "22 Mar", "Tampa, FL")); contestList.addContest(new Contest("ride", "29 Mar", "Cheyenne, WY")); contestList.addContest(new Contest("sail", "30 Mar", "Santa Cruz, CA")); // Get the locations of the contests. List<String> locs = contestList.getLocations(); System.out.println("locs = " + locs); } } class Contest { String name; String date; String location; Contest(String name, String date, String location) { this.name = name; this.date = date; this.location = location; } public String getLocation() { return location; } } class ContestList { List<Contest> list = new ArrayList<Contest>(); public void addContest(Contest contest) { list.add(contest); } public List<String> getLocations() { List<String> allLocations = new ArrayList<String>(); for(int j = 0; j < list.size(); j++) { Contest contest = (Contest)list.get(j); String location = contest.getLocation(); // Avoid duplicate locations. if(!allLocations.contains(location)) { allLocations.add(location); } } return allLocations; } }
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