Copying elements in an array

[Blondedude092]

How would i copy all the elements in

char arr1[] = {'x','y','z'};

into the last slots of

char arr2[] = new char[26];

**Failed to mention that I have to be able to do this all in one statement. Meaning looping is out of the question.

[Fubarable]

Use a for loop and a very little bit of arithmetic to figure out where your for loop index should start and end. Hint: you'll need to use the length of both arrays for this. You'll also need to use a different value for your arr1 and your arr2 indices, again calculated with a small amount of arithmetic.

[Blondedude092]

Ah, Yea, I know that it can be done with a for loop and having that copy into that yet I'm told that it can be done all in one statement; without loops.

[Fubarable]

Ah yes, but of course. System.arraycopy(...) will do this for you in one fell swoop. Please have a look here: System.arraycopy API

[Blondedude092]

I'm not sure if this qualifies as a single statement...

char arr1[] = {'x','y','z'};
        char arr2[] = new char[26];

        for(int i = 1; i <4;i++)arr2[22+i] = arr1[i-1]

also this

for(int i = 0; i <3;i++)arr2[23+i] = arr1[i];

[Fubarable]

No. You can place all your statements on one line and they still won't be a single statement. Again use System.arraycopy(...) for your single statement.

[Blondedude092]

System.arraycopy(arr1, 0, arr2, 23, 3);

I got it I think! Thanks!!

[Fubarable]

You've almost got it. If this were my code, I'd get rid of the "magic" numbers 23 and 3. I'd use the array lengths instead to calculate the method parameters. This makes for fewer bugs, especially if changes are made to the code in the future.